Answer:
The answer to your question is below
Explanation:
2.- 6
3.- Carbon
4.- These electrons can be share to obtain stability.
5.- Protons, electrons
6.- electron cloud
7.- I and III
8.- 1
9.- 8A
10.- 4
11.- F
12.- F
13.- F
14.- T
15.- T
16.- T
17.- T
18.- T (I can not read the question but I think is true)
Explanation:
The given data is as follows.
Weight of solute = 75.8 g, Molecular weight of solute (toulene) = 92.13 g/mol, volume = 200 ml
- Therefore, molarity of toulene is calculated as follows.
Molarity =
=
= 4.11 M
Hence, molarity of toulene is 4.11 M.
- As molality is the number of moles of solute present in kg of solvent.
So, we will calculate the molality of toulene as follows.
Molality =
=
= 8.6 m
Hence, molality of given toulene solution is 8.6 m.
- Now, calculate the number of moles of toulene as follows.
No. of moles =
=
= 0.8227 mol
Now, no. of moles of benzene will be as follows.
No. of moles =
=
= 1.2239 mol
Hence, the mole fraction of toulene is as follows.
Mole fraction =
=
= 0.402
Hence, mole fraction of toulene is 0.402.
- As density of given solution is 0.857 so, we will calculate the mass of solution as follows.
Density =
0.857 = (As 1 = 1 g)
mass = 171.4 g
Therefore, calculate the mass percent of toulene as follows.
Mass % =
=
= 44.22%
Therefore, mass percent of toulene is 44.22%.
PH + pOH = 14
11.8 + pOH = 14
pOH = 14 - 11.8
pOH = 2.2
[OH-] = 10 ^- pOH
[OH-] = 10 ^- 2.2
[OH-] = <span>6.33 x 10^-3 M
</span>
Answer B
hope this helps!
Answer:
The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L
Explanation:
The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L
The third problem would be the same steps as the second one.
The fourth problem would be (0.460M)(5.50L)= 2.53 moles