I think the answer is D no change. Though you add more CO2, but the pressure is not mentioned. If the pressure is constant and the reaction is already balanced, the H2O is also saturation and can not absorb more CO2.
The answer could possibly be D.) The product have more potential than the activated complex OR C.) Forming the activated complex requires energy .
Answer:
12 grams of hydrogen gas
and 56 grams of nitrogen gas
The molar mass of ammonia is 17 g/mol.
68 grams of ammonia corresponds to
17g/mol
68g
=4moles
4 moles of ammonia will be obtained from
2
4×1
=2 moles of nitrogen and
2
4×3
=6 moles of hydrogen.
The molar masses of nitrogen and hydrogen are 28 g/mol and 2 g/mol respectively.
2 moles of nitrogen corresponds to 2×28=56 grams.
6 moles of hydrogen corresponds to 6×2=12 grams.
Answer : The correct answer is 74.83 m/s .
The kinetic energy is energy possessed by any mass which is moving or have some speed . It is product of mass and velocity . It is expressed as :
![KE = \frac{1}{2} * m* v^2](https://tex.z-dn.net/?f=%20KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20m%2A%20v%5E2%20)
Where KE = kinetic energy in J or
m = mass in Kg v = speed in m/s²
Unit of KE is Joules (J) .
Givne : KE = 2100 J mass = 0.75 kg v = ?
Plugging value in KE formula =>
![2100 J = \frac{1}{2} * 0.75 Kg * v^2](https://tex.z-dn.net/?f=%202100%20J%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%200.75%20Kg%20%2A%20v%5E2%20%20)
![2100 J = 0.375 Kg * v^2](https://tex.z-dn.net/?f=%202100%20J%20%3D%200.375%20Kg%20%2A%20v%5E2%20)
Dividing both side by 0.375 kg =>
![\frac{2100 J}{0.375 Kg} = \frac{0.375 Kg}{0.375 Kg } * v^2](https://tex.z-dn.net/?f=%20%5Cfrac%7B2100%20J%7D%7B0.375%20Kg%7D%20%20%3D%20%5Cfrac%7B0.375%20Kg%7D%7B0.375%20Kg%20%7D%20%2A%20v%5E2%20%20%20)
![v^2 = 5600 \frac{m^2}{s^2}](https://tex.z-dn.net/?f=%20v%5E2%20%3D%205600%20%5Cfrac%7Bm%5E2%7D%7Bs%5E2%7D%20%20)
![v= 74.83 \frac{m}{s}](https://tex.z-dn.net/?f=%20v%3D%2074.83%20%5Cfrac%7Bm%7D%7Bs%7D%20%20%20)
Explanation:
measuring the change of temperature when 2 liquids are mixed