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2 years ago

7

You are asked to determine the identity of an unknown liquid and can measure only one physical property. you heat a liquid and r

ecord the liquid turns to vapor at 100 Celsius: this demonstrates which physical property?

1 answer:

Licemer1 [7]2 years ago

5 0

This demonstrates the boiling point. The substance changes from liquid to gas which is the point of vaporization and since it is from heat, it is boiling.

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Water boils at rate of ........and freeze at ........

Schach [20]

100 degree celcius and 0 degree Celsius

7 0

2 years ago

7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.

Effectus [21]

<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

The units used to measure length include;

Kilometer(km)

10

Hectometer (Hm)

10

Decameter (dkm)

10

Meter(m)

10

Decimeter (dm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

7 0

2 years ago

Read 2 more answers

How much time would it take to distribute one avagadro's number of wheat grains if 10^10 grains are A)1.9*10^2 years B)1.9*10^10

Makovka662 [10]

Answer:

It takes 1.9 $\times 10^{6}$ years to distribute all the grains.

Explanation:

In one second, $10^{10}$ grains of wheat are distributed.

We are supposed to find the time it would take to Distribute Avogadro number of grains.

1 avogadro number = 6.022 $\times 10^{23}$

Number of grains distributed in 1 day = 86400 $\times 10^{10}$

= 8.64 $\times 10^{14}$

Number of grains distributed in 1 year= 8.64 $\times 10^{14} \times 365$

= 3.1536 $\times 10^{17}$

Time taken = $\frac{Number of grains to be distributed}{grains distributed in 1 year}$

= $\frac {6.022 \times 10^{23}}{3.1536\times 10^{17}}$

= 1.9 $\times 10^{6}$

7 0

2 years ago

Write the following number in Standard (Numeric) Form. 5.8x10-5

DerKrebs [107]

Answer:

the answer of this question is 0.000058

4 0

2 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

8 0

2 years ago

Read 2 more answers