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2 years ago

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40% of students in a class are left-handed. Find the probability that the random sample of 20 Students in a class will have. (a)

At least 5 Left-handed (b) Less than Four left-handed (c) Exactly 6 Left-handed students, apply correction for continuity for only C.

2 answers:

Maurinko [17]2 years ago

5 0

I am left Handed!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

kkurt [141]2 years ago

5 0

Answer:

40% of 20 is 8

Step-by-step explanation:

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Which choice is equivalent to the quotient below shown here when x>0?

qwelly [4]

Answer:

Choice B is correct

Step-by-step explanation:

The given radical division can be expressed in the following form;

$\frac{\sqrt{16x^{3} } }{\sqrt{8x} }$

Using the properties of radical division, the expression can be expressed in the following form;

$\sqrt{\frac{16x^{3} }{8x} }=\sqrt{2x^{2} }$

Simplifying further yields;

$\sqrt{2x^{2} }=\sqrt{2}*\sqrt{x^{2} }=x\sqrt{2}$

Choice B is thus the correct alternative

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3 years ago

Read 2 more answers

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

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3 years ago

What are the solutions of the equation (x - 6) (x - 8) =8

enot [183]

Answer:

x=4 x=10

Step-by-step explanation:

(x - 6) (x - 8) =8

We need to multiply out the left side

x^2 -8x -6x+48 = 8

x^2 -14x +48 = 8

Subtract 8 from each side

x^2 -14x +48-8 = 8-8

x^2 -14x+40 =0

We need to factor the left side. What two numbers multiply to give 40 and add to give -14

-4*-10 = 40

-4+-10 = -14

(x-4) (x-10) =0

Using the zero product property

x-4=0 x-10 =0

x=4 x=10

8 0

3 years ago

Determine if the function f(x)=x+4 is increasing or decreasing on the interval of 2≤x≤5. Justify your answer.

Rudik [331]

Step-by-step explanation:

Given

The function is $f(x)=x+4$

for $x_2>x_1$ , we will check the values of $f(x_1)$ and $f(x_2)$

Take 3 and 4

$f(4)=4+4\\f(4)=8$

Similarly,

$f(3)=3+4\\f(3)=7$

Thus, $f(4)>f(3)$

Also, $f'(x)$ is 1 i.e. a constant value. So, the function is increasing linearly for the given interval.

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2 years ago

Find an equation for a line that is normal to the graph of y=xe^x and goes through the origin

Marina CMI [18]

Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin

3 0

3 years ago