Answer:
(C)19
Step-by-step explanation:
The diagram is drawn and attached.
Using the intersecting chord theorem
SL X LT = JL X LK
x X 12 = 14(x-1)
12x=14x-14
12x-14x=-14
-2x=-14
x=7
Therefore:
ST= SL + LT
=x+12
=7+12
ST=19
The correct option is C
The square root of 36/100 is c. -6/10 and 6/10
You can get this by using a calculator.
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Answer:
c
Step-by-step explanation:
Ok, the first clue is it has six digit and the second clue is it’s a whole number!
So we know it lies between 99999 and 1000000
3rd clue tells it has only 3 different digits and 4th clue tells us each are used twice!
Moving on, 5th clue says none of its digits are even! 6th speaks none are divisible be 3
So the possibilities for digits are 1, 5, 7
And it’s greater than 600000, then the 1st digit must be 7! It is divisible be 5, so last digit must be 5!
7th clue states that It’s tenth digit is same as hundred-thousand! Means the tenth digit is 7
Let’s see what we got!
{7xxx75}
Clue no 8 as you can see says that it’s thousands digit is same as unit digit
So the number now is {7x5x75}
9th clue says it’s hundreds digit is different from tens digit meaning the hundreds digit is either 1 or 7 and we used 7 two times, so it’s 1 and clue 10 says it’s ten thousands digit is 1 so the number that’s playing hide ‘n seek or most probably riddle game is 715175!
Answer:
H. 95°
Step-by-step explanation:
m∠BGC is 10° smaller than m∠CGD, which means that m∠BGC is x° - 10°
m∠DGE is 25° more than m∠EGF, which means that m∠DGE is x° + 25°
The sum of all angles in a placement like this will always equal 360°
So we put all the measures of all angles on one side of thee equation and set it equal to 360*
x° + x° - 10° + 2x° + 25° + 2x° + 3x° + 30° = 360°
After combining like terms we get 9x° + 45° = 360°
After some algebra we get x = 35°
Now at the start we said that m∠DGE is x + 25°
Plug in 35° for x and we get 35° + 25°
The final answer is m∠DGE = 95°
Edit: Sorry if my answer looks a bit confusing. This is actually my first answer on Brainly so I'm quite new to this experience.