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labwork [276]
3 years ago
12

DNA synthesis involves unwinding two strands of parent DNA, copying each strand to synthesize complementary strands, and release

of parent and daughter DNA. Which of the following accurately describes this process. Is this Anabolic or catabolic reaction
Biology
1 answer:
brilliants [131]3 years ago
3 0

Answer:

This is an anabolic process.

Explanation:

DNA replication involves unwinding two strands of parent DNA, copying each strand to synthesize complementary strands, and releasing the parent and daughter DNA. Thus, it is an anabolic process.

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The term used to identify identical strands of DNA held together by a centromere
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<span>The two identical chromosomes that result from DNA replication are referred to assister chromatids. Sister chromatids are held together by proteins at a region of the chromosome called the centromere.</span>
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Which is a major by product of respiration? Choose the correct answer.
lana66690 [7]

Answer:

This question is incomplete as it lacks options, however, it can be answered. The answer is:

CARBON DIOXIDE (CO2)

Explanation:

Cellular respiration is the process by which glucose is broken down in an organism's cell to release energy. Although the process involves series of reactions, however, the general equation is as follows;

C6H12O6 + 6O2 ➡ 6CO2 + 6H2O + energy

Based on the above equation, the inputs are glucose and oxygen while the outputs are carbon dioxide and water. Carbon dioxide (CO2) is the major byproduct of the respiration process.

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3 years ago
Write an Alternative Title for the Lesson 'This is Jody's Fawn'.
Lapatulllka [165]

Answer:

"This is jody's brown deer"

Explanation:

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3 years ago
¿ como se llama el gas que daña la atmósfera ?​
Nana76 [90]

Answer:

Gases that lead to air pollution include carbon, nitrogen and sulfur oxides. Explanation:

3 0
3 years ago
1. What is the total magnification of an object if the ocular lens magnification is 20x and the objective lens magnification is
V125BC [204]

1. Answer: 900x

A typical microscope has two lens: ocular lens which located near the eye, and objective lens which located near the object. The image will undergo magnification of both lens. The total magnification of the object would be the product of both lens multiplication, not the sum. The multiplication will be: 20x * 45x= 900x

total mag= ocular * object

total mag= 20x * 45x

total mag= 900x


2.  Answer: 100x

The total magnification of the object would be the product of both lens multiplication. If the total magnification 1000x, that mean it was the product of ocular lens and objective lens. If ocular lens magnification is 10x, objective lens magnification would be:

total mag= ocular * object

1000x= 10x*object

object=1000x/ 10x=

object=100x

3. Answer: 0.2 mm

The area of the microscope that can be viewed by the eye should be the same. But since the magnification is different, the actual area that it represent will be different. Microscope with bigger magnification will have smaller diameter of the field of view(DFV).  Remember that micrometer(μm) is 1/1000 of millimeter(mm). The DFV would be:500 μm/ ( 1000x/400x)= 200μm= 0.2 mm


4. Answer: 750μm

This question is similar to number 3 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm) .

The DFV of a 10x objective lens is 3 mm. Then the DFV of 40x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 3mm/ ( 40x/10x)= 0.75 mm= 750μm

5. Answer: 125μm x 37.5μm

The lens DFV of microscope from question 4 is 750μm, so the width and length of the area would be 750μm.

If 6 organisms could fit across the DFV if they were laid end-to-end, the length would be: 750μm/ 6 organism= 125μm

If 20 organism could fit is stacked side by-side, then the width would be: 750μm/ 20 organism= 37.5μm

6. Answer: 6mm

This question is similar to number 3 and number 4 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm).

The DFV of a 100x objective lens is 1.5 mm. Then the DFV of 25x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 1.5mm/ (100x/25x)= 6 mm


7.Using the 100x objective lens from question 6, you estimate 12 organisms could fit across the DFV if they were laid end-to-end and 30 could fit is stacked side-by-side. What is the length and width of this organism (in microns)?  

Answer: 0.5mm x 0.2mm or 500μm x 200μm

The lens DFV of microscope from question 6 is 6 mm, so the width and length of the area would be 6 mm.

If 12 organisms could fit across the DFV if they were laid end-to-end, the length would be: 6mm/ 12 organism=0.5mm

If 30 organism could fit is stacked side by-side, then the width would be: 6mm/ 30 organism= 0.2mm

6 0
3 years ago
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