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2 years ago

I need help with this graph

Mathematics

2 answers:

Alchen [17]2 years ago

6 0

Answer:

D. The scuba diver was 35 meters below the surface when she started her ascent

lord [1]2 years ago

6 0

Answer:

D) The scuba diver was 35 meters below the surface when she started her ascent

Step-by-step explanation:

It's not A, it looks like it at first but then if you follow through you'll see that it's not the case

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-5, 20, -80, 320, ... is a geometric sequence a. Find the common ratio, b. Write its recursive rule c. Write its explicit rule.W

mario62 [17]

In order to find the common ratio, we just need to divide a term by the term that comes before it.

So using the terms 20 and -5, we have:

$\text{ratio}=\frac{20}{-5}=-4$

The recursive rule can be found with the formula:

$a_n=a_{n-1}\cdot q$

Where an is the nth term and q is the ratio. So we have:

$a_n=a_{n-1}\cdot(-4)$

The explicit rule can be written as:

$a_n=a_1\cdot q^{n-1}$

Where an is the nth term, a1 is the first term and q is the ratio. So:

$a_n=-5\cdot(-4)^{n-1}$

5 0

4 months ago

How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

4 0

2 years ago

The walls of the kitchen are 8 feet tall. You will only paint three wLLA OF THE KIRCHEN. WHAT IS THE TOTAL WALL AREA OF THE THRE

Anika [276]

You need to include how wide the walls are. but once you find how wide the walls are (X) then multiply it by how tall a the walls are (8 feet) and you will get the area of one wall. Take that answer and multiply it by 3 then multiply that by how much the paint costs

6 0

2 years ago

1) What are the solutions of (x/3) > -1? <br><br>is this asking if I need multiple solutions?

BartSMP [9]

Yes...

x/3 > -1

what values of x make x/3 > -1

hint... your answer will look like like x > (number)

7 0

2 years ago

(Middle school math) please help, thank you!

valentina_108 [34]

Answer:

i dont know

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers