<h2>
Hello!</h2>
The answer is:
The fourth graph.
<h2>
Why?</h2>
We are given the following equation:

Then, we need to find the graph of f(x+2) that will be equal to:


Now, finding the x-axis interception, making "y" equal to 0, we have:


Therefore, the x-axis interception point is located at (-2,0), it matches with the fourth graph.
Now, finding the y-axis interception, making "x" equal to 0, we have:


Therefore, the y-axis interception point is located at (0,2), it matches with the fourth graph.
Hence, we have that the graph of f(x+2) is the fourth graph since the second graph function cuts the x-axis at -2 and the y-axis at 2.
Have a nice day!
Answer:
$12.79
Step-by-step explanation:
$45 - $18.63 = $26.37
$26.37 - ($.47 x 2) = $26.37 - $.94 = $25.43
$25.43 - $12.64 = $12.79
I believe 22. Because 11+3=14, but without that, you would add 11 to 11, which gives you 22
Answer:
Graph B.
Step-by-step explanation:
this is nonlinear because you cannot connect or create a line with where the dots are plotted if that makes sense.
hope this helps!
Answer:

<h2>Not sure!! I don't know this asnwer is wrong or right.</h2>