The complete table will be:
<u><em>Explanation</em></u>
Suppose, the number of sit-ups in Sunday is 
Mean is the simple average of some numbers. <u>For finding the mean number</u> of sit-ups per day, we need to <u>divide the 'total number of sit-ups' by the 'total number of days'</u>.
Here the total number of days is 7 and the total number of sit-ups for 7 days 
Given that, the mean number of sit-ups per day is 100. So, the equation will be...
So, the number of sit-ups you have to do Sunday is 175.
Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.
Let x be the number of $2 increases in price, then the revenue from renting cars is given by
.
Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by
Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
</span><span>
For maximum profit, the differentiation of the profit function equals zero.
i.e.
</span><span>
The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.
Therefore, the </span><span>rental charge will maximize profit is $64.</span>
1km=1000metres
15km=15000 metres
15000/600=25
25-1=24 (minus the last one)
hope this helps :)
I'm probably not right, but that appears to be already rounded to the nearest tenth.
