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3 years ago

13

Hello, how are you? I hope you are well. I wanted to ask you if you could help me answer these divisions? Please I would really

appreciate it.
5.4078÷28 = Answer:

0.62409÷45= Answer:

9.0804÷60= Answer:

(Please, I need everything step by step. )

1 answer:

Bogdan [553]3 years ago

6 0

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The value of X in the figure ABCD witch is a rhombus

NeX [460]

Answer:

x = 10°

Step-by-step explanation:

The diagonals of a rhombus divide the figure into congruent right triangles. That means the two marked acute angles are complementary.

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<h3>solve for x</h3>

Complementary angles total 90°, so the relation we can use to find x is ...

(3x -13) +(8x -7) = 90

11x = 110 . . . . . . . . . add 20

x = 10 . . . . . . . . . divide by the coefficient of x

The value of x is 10°.

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2 years ago

Will mark brainliest! Questions are in the picture!

alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the <u>perimeter </u>to the nearest tenth.

As we know that the area of triangle is ,

$\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)$

Substituting the respective values,

$\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0$

On using the <u>Quadratic</u><u> formula</u> , we have;

$\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}$

On simplifying above , we will get ,

$\rm\longrightarrow x = 6.802,-9.802$

Since sides can't be negative, therefore,

$\rm\longrightarrow\underline{\underline{ x =6.802}}$

Therefore ,

$\rm\longrightarrow Base = 3x =3(6.802)in = 20.406\ in\\$
$\rm\longrightarrow Height = x +3=6.802+3=9.802\ in$

Next let's find out the <u>hypotenuse </u>using Pythagoras theorem, as ;

$\rm\longrightarrow h=\sqrt{ b^2+p^2}\\$

$\rm\longrightarrow h =\sqrt{ (20.406)^2+(9.802)^2}\\$

$\rm\longrightarrow h =\sqrt{416.40+96.07}\\$

$\rm\longrightarrow h = 22.63\ in$

Now we may find perimeter as ,

$\rm\longrightarrow P = p + b + h \\$

$\rm\longrightarrow P = (22.63 + 9.802 + 20.406)in.$

$\\\rm\longrightarrow P = 52.89 \ in.\\$

$\rm\longrightarrow \underline{\underline{ Perimeter = 52.9\ in .}}$

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2 years ago

Dy/dx ln(xy)=e^(x+y)

Westkost [7]

In(xy) = e^(x+y)

(xy)'/xy = (x+y)' e^(x+y)

(x'y + xy')/xy = (1+y') e^(x+y)

(y + xy')/xy = (1+y')e^(x+y) and simplify

Hope this helps

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3 years ago

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Paladinen [302]

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3 years ago

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dimaraw [331]

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Step-by-step explanation:

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3 years ago