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Blizzard [7]
3 years ago
5

Please help me with number 8

Mathematics
1 answer:
AlekseyPX3 years ago
3 0

Answer:

jjejejkwkwkqkkqkqkqkkqkqkq

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<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%7D%20%287%5Csqrt%5B3%5D%7B8y%5E2%7D-%5Csqrt%5B3%5D%7By%5E5%7D%20-4y%5Csqrt%
noname [10]

Answer:

\huge\boxed{-y^2+2y}

Step-by-step explanation:

\sqrt[3]y\cdot\left(7\sqrt[3]{8y^2}-\sqrt[3]{y^5}-4y\sqrt[3]{27y^2}\right)\\\\=(\sqrt[3]y)(7\sqrt[3]{8y^2})-(\sqrt[3]y)(\sqrt[3]{y^5})-(\sqrt[3]y)(4y\sqrt[3]{27y^2})\\\\=7\sqrt[3]{(y)(8y^2)}}-\sqrt[3]{(y)(y^5)}-4y\sqrt[3]{(y)(27y^2)}\\\\=7\sqrt{8y^3}-\sqrt{y^6}-4\sqrt{27y^3}\\\\=7\sqrt[3]{2^3y^3}-\sqrt{y^{2\cdot3}}-4\sqrt{3^3y^3}\\\\=7\sqrt[3]{(2y)^3}-\sqrt{(y^2)^3}-4\sqrt{(3y)^3}\\\\=7\cdot2y-y^2-4\cdot3y\\\\=14y-y^2-12y\\\\=-y^2+2y

Used:

a(a+b)=ab+ac\\\\\sqrt[3]{a\cdot b}=\sqrt[3]a\cdot\sqrt[3]b\\\\\sqrt[3]{a^3}=a\\\\(a^n)^m=a^{n\cdot m}

7 0
2 years ago
Kiras kayaks charges it's customers $8 per hour, but it gives a $5 discount to any customer who rents a kayak for at least 2 hou
cricket20 [7]

Answer:

$20

Step-by-step explanation:

if you look at the graph it shows that cappie canoes charges $25 for 3 hours but for every 2 hours they get a $5 discount so 25-5=20

8 0
3 years ago
Leo wants to buy a house for 128000 with a 20% down payment. How much will his down payment be
Alinara [238K]

128000 x .2= 25,600

Your down payment 25,600.

3 0
3 years ago
Read 2 more answers
30-5 • 4+2 how do I solve this
Alona [7]
P
E
M
D
A
S

5*4= 20
20+2=22
22-30= answer is 8 :)
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=10x-16y%3D12%20%5C%5C%205x-3y%3D4" id="TexFormula1" title="10x-16y=12 \\ 5x-3y=4" alt="10x-16y
Molodets [167]

Answer:

24/25

Step-by-step explanation:

Step 1: Define systems of equation

10x - 16y = 12

5x - 3y = 4

Step 2: Rewrite one of the equations

5x = 4 + 3y

x = 4/5 + 3y/5

Step 3: Solve for <em>y</em> using Substitution

  1. Substitute 2nd rewritten equation into 1: 10(4/5 + 3y/5) - 16y = 12
  2. Distribute the 10 to both terms: 40/5 + 30y/5 - 16y = 12
  3. Simplify the fractions down: 8 + 6y - 16y = 12
  4. Combine like terms (y): 8 - 10y = 12
  5. Subtract 8 on both sides: -10y = 4
  6. Divide both sides by -10: y = 4/-10
  7. Simply the fraction down: y = -2/5

Step 4: Substitute <em>y</em> back into an original equation to solve for <em>x</em>

  1. Substitute: 5x - 3(-2/5) = 4
  2. Multiply: 5x + 6/5 = 4
  3. Subtract 6/5 on both sides: 5x = 14/5
  4. Divide both sides by 5: x = 14/25

Step 5: Check to see if solution set (14/25, -2/5) is a solution.

  1. Substitute into an original equation: 10(14/25) - 16(-2/5) = 12
  2. Multiply each term: 28/5 + 32/5 = 12
  3. Add: 12 = 12

Here, we see that x = 14/25, y = -2/5 and solution (14/25, -2/5) indeed works.

Step 6: Find <em>x</em> <em>- y</em>

x = 14/25

y = -2/5

  1. Substitute: 14/25 - (-2/5)
  2. Simplify (change signs): 14/25 + 2/5
  3. Add: 24/25

Hope this helped! :)

6 0
3 years ago
Read 2 more answers
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