Mean = 0.497 in, SD = 0.003 in
Required diameter ranges between 0.496 in and 0.504 in
Anything other diameter obtained is not acceptable.
That is;
P(x<0.496) and P(x>0.504) are not acceptable.
Now,
P(x<0.496) = P(Z< (0.496-0.497)/0.003)) = P(Z<-0.33)
From Z tables, P(Z<-0.33) = 0.3707
Similarly,
P(x>0.504) = P(Z> (0.504-0.497)/0.003)) = P(Z>2.33)
From Z tables, P(Z>2.33) = 1-0.9901 = 0.0099
Therefore, unacceptable proportion = P(x<0.496)+P(x>0.504) = 0.3707+0.0099 = 0.3806 or 38.06%
Answer:
AB = CD
BC = DA
Step-by-step explanation:
Since 3x+2 = 5x-2, solving for x yields 2. Since BC = 4x+1 = DA, BC and DA both equal 4(2)+1 = 9.
13 should be b and
14 is a because geometric mean to have a common ratio