Answer:
16
Step-by-step explanation:
Given
C=2r and r=8
So
C=2×8 (as r=8)
C=16 (ans)
12,500 / 100 = 125 125 x 4.5 = 562.5 562.5 x 4 = 2250
2250 + 12,500 = 14,750 He paid back a total of $14,750. Hope this helps :)
Answer:
The digit 4 should be in the thousand position in the number sought;
Examples
9.30<u>4</u>,
9.00<u>4</u>
Step-by-step explanation:
Here, we are required to consider decimal places of numbers
The digit 4 in the number 3.8463 is in the hundredth position
That is 0.04
We are asked to look for the number with a digit 4 that has the same value as
the digit 4 in 3.8463
That is
![\frac{1}{10} \times 0.04 = 0.004](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%20%20%5Ctimes%200.04%20%3D%200.004)
Therefore, the digit 4 in the number sought should be in the thousandth position, that is 0.004
Example includes 9.304 or 9.004.
Answer:
2.5
Step-by-step explanation:
The minimum value is the minimum y-value a function includes. In this case, since you can see the function is periodic (it repeats itself <em>periodically</em>, hence periodic) and the smallest y-value the function encounters is 2.5 (doesn't go below this value), the minimum y-value is 2.5. I hope this made sense. If not, feel free to let me know.
Answer:
probability that a randomly selected page that contains only text will contain no typos that is
P(x=0) =
= 0.923
Step-by-step explanation:
<u>Poisson distribution</u>:-
Explanation of the Poisson distribution :-
The Poisson distribution can be derived as a limiting case of the binomial
distribution under the conditions that
i) p is very small
ii) n is very large
ii) λ = np (say finite
The probability of 'r' successes = ![\frac{e^{-\alpha }\alpha^r }{r!}](https://tex.z-dn.net/?f=%5Cfrac%7Be%5E%7B-%5Calpha%20%7D%5Calpha%5Er%20%20%7D%7Br%21%7D)
Given the average number of typos ∝ = 0.08 per page.
probability that a randomly selected page that contains only text will contain no typos that is = ![p(x=0) = \frac{e^{-0.08 }\(-0.08)^0 }{0!}](https://tex.z-dn.net/?f=p%28x%3D0%29%20%3D%20%5Cfrac%7Be%5E%7B-0.08%20%7D%5C%28-0.08%29%5E0%20%20%7D%7B0%21%7D)
After calculation P(x=0) =
= 0.923
probability that a randomly selected page that contains only text will contain no typos =0.923