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siniylev [52]
2 years ago
15

Please help I hate geometry

Mathematics
2 answers:
finlep [7]2 years ago
7 0

transverse s at angle 135°

180° - 135° = 45°

Angle 2 is congruent to 45° because they're alternate exterior angles.

transverse t at angle 120°

180° - 120° = 60°

Angle 3 is congruent to 60° because they're alternate exterior angles.

One rule for exterior angles in triangles is that the exterior angle is equal to the sum of the two angles adjacent to the opposite angle of the exterior angle.

135° = angle 1 + 60°

angle 1 = 75°

120° = angle 1 + 45°

angle 1 = 75°

Therefore angle 1 is 75°,angle 2 is 45° and angle 3 is 60°

lesya [120]2 years ago
3 0

Answer:

m∠1 = 75° m∠2 =45° m∠3 = 60°

Step-by-step explanation:

m∠1 = 180 - { (180 - 135) + (180 - 120) }

m∠1 = 180 - { 45 + 60 }

m∠1 = 75°

The angle between 1 and 3, lets call it x,  is vertically opposite to ∠2, so we must find it first to be able to get ∠2

Since a ║b

Therefore ∠x and ∠135 are co-interior angles

Therefore ∠x = 180-135

m∠x = 45°

∠2 = ∠x (Vertically opposite angles)

∠2 = 45°

Between ∠2 and ∠3 there is an angle, let's call it z.

∠z = ∠1 (Vertically opposite angles)

∠z = 75°

Since the sum of  ∠2, ∠z and ∠3 = 180° (Straight angle)

Therefore m∠3 = 180 - (∠2 + ∠z)

m∠3 = 180 - (45 + 75)

m∠3 = 60°

Or in a different way

∠2 + ∠z + ∠3 = 180

45 + 75 + ∠3 = 180

120 + ∠3 = 180

∠3 = 180 - 120

∠3 = 60°

Hope it helps

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In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o
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A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

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Alternative hypothesis:p \neq 0.1  

C. z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

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Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

\hat p=\frac{33}{363}=0.0912 estimated proportion of orders not accurate

p_o=0.10 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

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Fail to the reject the null hypothesis

F: Write the conclusion of the test.

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