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maksim [4K]
3 years ago
13

Which table shows a proportional relationship between x and y?

Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer:

the third table listed here

Step-by-step explanation:

A "proportional" relationship has the same y/x ratio for all values of x and y.

... first table: all entries but one have y/x = 1/3. The 3rd entry has y/x = 0.4—not the same.

... second table: 6/4 ≠ 8/6

... third table: all entries reduce to y/x = 15

... fourth table: 3/2 ≠ 4/3

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Plz plz plz plz plz help peep
PilotLPTM [1.2K]

2³-4²

= 8-16

=-8

Hopefully this helps! Good luck! :)

6 0
2 years ago
Read 2 more answers
A researcher is studying a mouse population in a field. For the first year of her study, she notices that the mouse population d
Montano1993 [528]

Answer:

The 500 mice would be the carrying capacity of the field being studied.

Step-by-step explanation:

For the first year of study, the mouse population demonstrates exponential growth.

But by third year, the mouse population has stabilized at approximately 500 mice.

Thus, this 500 mice would be the carrying capacity of the field being studied.

Carrying capacity is defined as the measure to demonstrate the maximum population size that any given environment can sustain for an unspecified time period.

5 0
3 years ago
Show a way to count from 668 to 900 using ones, tens, and hundreds
zmey [24]

Answer

668 + 232 ones = 900

or

668 + 23 tens + 2 ones = 900

or

668 + 2 hundreds + 32 ones = 900

or

668 + 2 hundreds + 3 tens + 2 ones.

<u>Explanations</u>

900 - 668 = 232. Meaning we can add 232 ones to 668 to get 900.

232-200 = 32 ⇒ Meaning, we can add 2 hundreds and 32 ones to 668 to get 900.

32-30 = 2. This means we can add 2 hundreds, 3 tens and 2 ones to 668 to get 900.

900 - 668 = 232

4 0
3 years ago
Read 2 more answers
Quick, anyone know the answer?
SVETLANKA909090 [29]
Your answer would be A :)
4 0
3 years ago
Read 2 more answers
Without a calculator how would you solve this?
mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6

=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}

\bigstar\  (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}

\bigstar\  \bigstar\  (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}

\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702

\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6

0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0

\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0

\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702

8 0
2 years ago
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