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3 years ago

What is the value of this expression when n approaches infinity?

Mathematics

2 answers:

Georgia [21]3 years ago

7 0

Answer:

35 I just took the quiz

Step-by-step explanation:

topjm [15]3 years ago

4 0

ANSWER

C. 35

EXPLANATION

The given expression is:

$15 - 35 - \frac{85}{n} + 55 + \frac{75}{2n} + \frac{15}{2 {n}^{2} }$

$n \to \: \infty$

$\frac{k}{n} \to0$

where k is a constant.

This implies that,

$15 - 35 - \frac{85}{n} + 55 + \frac{75}{2n} + \frac{15}{2 {n}^{2} } = 15 - 35 - 0 + 55 + 0+ 0 =35$

The correct answer is C

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Find the value of c that makes the expression a perfect square trinomial.

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In a metal fabrication process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n

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Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, $\bar{x}$ = 14.8 feet

Sample size, n = 16

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Eight more then seventimes a number (x) is atleast twenty nine

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Answer:A number increased by seventeen is equal to seventy-three. x + 17 = 73

Some number decreased by seven is thirty-three. x - 7 = 33

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Eight less than a number is nine. x - 8 = 9

A number divided by 11 is 4. x/11 = 4

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Twelve more than four times a number is seven. 4x + 12 = 7

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Fifty-five is the sum of a number and sixteen. x + 16 = 55

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Eight times a number increased by eleven is thirty-seven. 8x + 11 = 37

The difference of a number and twelve is thirty-four. x - 12 = 34

Step-by-step explanation:

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3 years ago

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A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are

IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5 percent of these are defective.

This means that $p = 0.05$

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This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025$

0.0025 = 0.25% probability that both are defective

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3 years ago