Determine whether or not the relation is a function. Please help asap

Mathematics

1 answer:

OLga [1]2 years ago

4 0

Answer:

A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function

Step-by-step explanation:

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Find the equation of a line perpendicular to y=-4x that contains the point (-3, -4)

madam [21]

Use this for help y2-y1/x2-x1

don’t forgot to use a calculator if u have negative numbers

5 0

3 years ago

Find the average value of f over region

SVETLANKA909090 [29]

$D$ is a right triangle with base length 1 and height 8, so the area of $D$ is $\dfrac12(1)(8)=4$ .

The average value of $f(x,y)$ over $D$ is given by the ratio

$\dfrac{\displaystyle\iint_Df(x,y)\,\mathrm dA}{\displaystyle\iint_D\mathrm dA}$

The denominator is just the area of $D$ , which we already know. The average value is then simplified to

$\displaystyle\frac74\iint_Dxy\,\mathrm dA$

In the $x,y$ -plane, we can describe the region $D$ as all points $(x,y)$ that lie between the lines $y=0$ and $y=8x$ (the lines which coincide with the triangle's base and hypotenuse, respectively), taking $0\le x\le1$ . So, the integral is given by, and evaluates to,

$\displaystyle\frac74\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=\frac78\int_{x=0}^{x=1}xy^2\bigg|_{y=0}^{y=8x}\,\mathrm dx$
$=\displaystyle56\int_{x=0}^{x=1}x^3\,\mathrm dx$
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3 0

3 years ago

What is the degree of this polynomial? 4m^8-9m^6+3m^9-6m^7

Klio2033 [76]

Answer:

this is a ninth degree polynomial in m

Step-by-step explanation:

Inspect the polynomial for the highest power of the variable m. It is m^9. Thus, this is a ninth degree polynomial in m.

7 0

2 years ago

Please help! 11 pts.

77julia77 [94]

Hey user!!!

given the radius of the cylindrical mold is 2 inches and height is 3 inches.

volume of the cylindrical mold = πr²h

= 3.14 × 2 × 2 × 3

= 37.68 in³

radius of the spherical mold is given = 2 inches

volume of the spherical mold = 4/3πr³

= 4/3 × 3.14 × 2 × 2 × 2

= 100.48/3 in³

difference between the amount of wax needed = 37.68/1 - 100.48/3

= ( 113.04 - 100.48 ) / 3

= 12.56/3

= 4.186...

so approximately 4.19 in³

hence, correct option is 4.19 in³

cheers!!!

8 0

4 years ago

Read 2 more answers

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xxTIMURxx [149]

Answer:

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