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3 years ago

Determine whether or not the relation is a function. Please help asap

Mathematics

1 answer:

OLga [1]3 years ago

4 0

Answer:

A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function

Step-by-step explanation:

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Please help!!

azamat

Answer:

$sin \theta = \frac{\sqrt {19}}{10}$

Step-by-step explanation:

$( \sin \theta) ^{2} + ( \cos \theta) ^{2} = 1 \\ \\ \therefore \:( \sin \theta) ^{2} + { \bigg( \frac{{9} }{10} \bigg)}^{2}= 1 \\ \\( \sin \theta) ^{2} + \frac{81}{100}= 1 \\ \\ ( \sin \theta) ^{2} = 1 - \frac{81}{100} \\ \\ ( \sin \theta) ^{2} = \frac{100 - 81}{100} \\ \\ ( \sin \theta) ^{2} = \frac{19}{100} \\ \\ \sin \theta = \sqrt{\frac{19}{100} } \\ \\ \sin \theta = \frac{\sqrt {19}}{10}$

7 0

3 years ago

George has a sum of money.

Daniel [21]

11:100
iwan:siobhan
if iwan gets 11% then iwan gets 89/100

3 0

3 years ago

What is the sum of -7/10 + 1/4

Allushta [10]

Exact form -9/20 or in decimal form is -0.45

4 0

3 years ago

For all of the Following use the function LaTeX: P\left(x\right)\:=\:\left(x+3\right)^2+2 . My original vertex is

PolarNik [594]

Answer:

A) Q(x) = (x + 3)² + 5, and the vertex is (-3, 5)

B) R(x) = (x - 3)² + 2, and the vertex is (3, 2)

C) S(x) = (x - 1)² - 5, and the vertex is (1, -5)

Step-by-step explanation:

The given function is P(x) = (x + 3)² + 2

The given function is a parabolic function in vertex form, f(x) = a·(x - h)² + k, and vertex, (h, k)

By comparison, the vertex of the function P(x) = (x + 3)² + 2 is (-3, 2)

A) A function f(x) translated α units UP gives

f(x) (translated α units UP) → f(x) + α

A translation of the function 3 units UP is given by adding 3 to the given function as follows;

Q(x) = P(x) + 3

∴ Q(x) = (x + 3)² + 2 + 3 = (x + 3)² + 5

Q(x) = (x + 3)² + 5, and the vertex by comparison to f(x) = a·(x - h)² + k, and vertex, (h, k) is (-3, 5)

B) A function f(x) translated b units RIGHT gives;

f(x) translated b units right → f(x - b)

∴ P(x) = (x + 3)² + 2 translated 6 units RIGHT gives;

P(x) = (x + 3)² + 2 (translated 6 units RIGHT) → R(x) = (x + 3 - 6)² + 2 = (x - 3)² + 2

R(x) = (x - 3)² + 2, and the vertex by comparison is (3, 2)

C) A function translated α units DOWN and b units RIGHT is given as follows;

$f(x) \ translated \ by\ \dbinom{b}{a} \rightarrow f(x - b) - a$

Therefore, the given function, P(x) = (x + 3)² + 2, translated 7 units DOWN and 4 units RIGHT gives;

$P(x) = (x + 3)^2 + 5 \ translated \ by\ \dbinom{4}{-7} \rightarrow P(x - 4) - 7 = S(x)$

S(x) = P(x - 4) - 7 = (x + 3 - 4)² + 2 - 7 = (x - 1)² - 5

$P(x) = (x + 3)^2 + 5 \ translated \ by\ \dbinom{4}{-7} \rightarrow (x - 1)^2 - 5= S(x)$

S(x) = (x - 1)² - 5, and the vertex by comparison is (1, -5)

7 0

3 years ago

What are the extremes of the following proportion? 3⁄15 = 12⁄60

pashok25 [27]

Answer:

3 and 60

Step-by-step explanation:

For the given proportions, $\frac { 3 } { 15 } = \frac { 12 } { 60 }$ , 3 and 60 are the extremes while 12 and 15 are the means.

To understand this, we can take a look at an example.

Suppose two ratios a:b and c:d are in proportion.Then it can be expressed as :

$ab=cd$

Here, a and d are the extreme ends and b and c are the means.

6 0

3 years ago