Answer:
the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.
Explanation:
When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.
Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.
The whole process must be analyzed using conservation of the moment.
p₀ = m v₀
celestines que clash case
p_f = (m + M) v
po = pf
m v₀ = (n + M) v
v = 
calculemos
v= 
v= 0.09 m/s
elastic shock case
p₀ = m v₀
p_f = m v₁ +M v₂
p₀ = p_f
m v₀ = m v₁ + m v₂
<span>Plug in 288 for h, move it over to the right side and do the quadratic formula to solve for t. You will get 2 times, in between and including those times will give you the period it is at least 288 ft off the ground.
</span>You can simplify this and not need to use the quadratic.
<span>288=−16<span>t^2</span>+144t
</span><span>Divide through by 16 getting
18=-t^2 + 9t
</span><span><span>t^2</span>−9t+18=0</span><span> Is what you would get after rearranging the equation Now you have something you can easily factor</span><span>
</span>
Answer:
The ball travels a distance of 20 m in the time interval of 4 s
Explanation:
Using s = ut + 1/2at² where s = distance travelled by the ball, u = initial velocity of ball = 0 m/s (since it starts from rest), a = acceleration of the ball = 2.50 m/s² and t = time = 4 s.
Substituting the variables into the equation, we have
s = ut + 1/2at²
s = 0 × 4 s + 1/2 × 2.50 m/s² × (4 s)²
s = 0 + 1/2 × 2.50 m/s² × 16 s²
s = 1/2 × 40 m
s = 20 m
So, the ball travels a distance of 20 m in the time interval of 4 s.
Answer:
The correct answer is violet, blue, green, and red emission lines.
Explanation:
When samples of pure elements are heated they emit a continuous spectrum of electromagnetic radiation. When elements are heated at very high temperatures, the electrons get excited and they jump to consequent orbits and this results in transmission of electromagnetic radiation. The four lines visible in the emission spectrum of hydrogen are violet, blue, green, and red, the most intense of which is at 656 nanometre.
