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Kobotan [32]
3 years ago
9

Explain why friction makes it harder to push a box filled with groceries than an empty box

Physics
1 answer:
kupik [55]3 years ago
5 0
It is harder to push a box with groceries in it because the mass is weighing the box down. Which makes it harder to push
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A nonzero net force acts on a particle and does work. Which one of the following statements is true?
arlik [135]

Answer:

option (D) is correct.

Explanation:

According to the work energy theorem, the work done by all forces is equal to the change in kinetic energy of the body.

the kinetic energy of a body is directly proportional to the square of the speed of the body.

As the kinetic energy change, the speed of the body also change.

Option (D) is correct.

5 0
3 years ago
A 400 N steel ball is suspended by a light rope from<br>the ceiling. The tension in the rope is​
alina1380 [7]

Answer:

As force = tension in string so tension in string is 400N

Explanation:

8 0
3 years ago
1
Darina [25.2K]

Answer:

7.5 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1  = 60kg

Mass 2  = 75kg

Distance between the bodies  = 2m

Unknown:

Gravitational fore  = ?

Solution:

The gravitational force between the two bodies can be derived using;

  F  = \frac{G mass 1 x mass 2}{distance^{2} }  

    G is the universal gravitation constant  = 6.67 x 10⁻¹¹m³kg⁻¹s⁻²

Insert the parameters and solve;

  F  = \frac{6.67 x 10^{-11}  x 60 x 75}{2^{2} }   = 7.5 x 10⁻⁸N

3 0
3 years ago
A golf ball strikes a hard, smooth floor at an angle of 28.2 ° and, as the drawing shows, rebounds at the same angle. The mass o
WITCHER [35]

Answer:

    I = 1.06886  N s

Explanation:

The expression for momentum is

          I = F t = Δp

therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor

Let's find the components of the initial velocity

          sin 28.2 = v_y / v

          cos 28.2=  vₓ / v

          v_y = v sin 282

          vₓ = v cos 28.2

          v_y = 42.8 sin 28.2 = 20.225 m / s

          vₓ = 42.8 cos 28.2 = 37.72 m / s

since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making

θ = -28.2

         v_y = -20.55 m / s

         v_x = 37.72 m / s

X axis

         Iₓ = Δpₓ = p_{fx} - p_{ox}

since the ball moves in the x-axis without changing the velocity, the change in moment must be zero

         Δpₓ = m v_{fx} - m v₀ₓ = 0

          v_{fx} = v₀ₓ

therefore

          Iₓ = 0

Y axis  

        I_y = Δp_y = p_{fy} -p_{oy}

when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards

         v_{fy} = - v_{oy}

         Δp_y = 2 m v_{oy}

         Δp_y = 2 0.0260 (20.55)

         \Delta p_{y} = 1.0686 N s

the total impulse is

          I = Iₓ i ^ + I_y j ^

          I = 1.06886  j^ N s

7 0
3 years ago
Can someone please here me I’m confused
Naddika [18.5K]
I would say z, x, y, w
5 0
4 years ago
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