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2 years ago

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A 4000 kg rocket is launched, shooting 50 kg of burned fuel from its exhaust at a velocity of -625 m/s. What is the velocity of

the rocket after the fuel has burned? (Ignore the effects of gravity as this rocket is in the deepest darkest regions of interstellar space)

1 answer:

AnnZ [28]2 years ago

8 0

Hopefully this will help you.

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The terminal velocity is not dependent on which one of the following properties? the drag coefficient 1 the force of gravity 2 c

ahrayia [7]

<h2>Answer: the falling time</h2>

Explanation:

When a body or object falls, basically two forces act on it:

1. The force of air friction, also called<em> </em><u><em>"drag force"</em></u> $D$ :

$D={C}_{d}\frac{\rho V^{2} }{2}A$ (1)

Where:

$C_ {d}$ is the drag coefficient

$\rho$ is the density of the fluid (air for example)

$V$ is the velocity

$A$ is the transversal area of the object

So, this force is proportional to the transversal area of the falling element and to the square of the velocity.

2. Its <u>weight </u>due to the gravity force $W$ :

$W=m.g$

(2)

Where:

$m$ is the mass of the object

$g$ is the acceleration due gravity

So, at the moment <u>when the drag force equals the gravity force, the object will have its terminal velocity:</u>

$D=W$ (3)

${C}_{d}\frac{\rho V^{2} }{2}A=m.g$ (4)

$V=\sqrt{\frac{2m.g}{\rho A{C}_{d}}}$ (5) This is the terminal velocity

As we can see, there is no "falling time" in this equation.

Therefore, the terminal velocity is not dependent on the falling time.

6 0

2 years ago

Calculate the acceleration of a 1000 kg car if the motor provides a small thrust of 1000 N and the static and dynamic friction c

grin007 [14]

Explanation :

It is given that,

Mass of the car, m = 1000 kg

Force applied by the motor, $F_A=1000\ N$

The static and dynamic friction coefficient is, $\mu=0.5$

Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,

$F_A-\mu mg=ma$

$\dfrac{F_A-\mu mg}{m}=a$

$a=\dfrac{1000-0.5(1000)(9.81)}{1000}$

$a=-3.905\ m/s^2$

So, the acceleration of the car is $-3.905\ m/s^2$ . Hence, this is the required solution.

6 0

2 years ago

Which statement accurately describes something that Yolanda can do as a part of her study?

Vikki [24]

Thank you for posting your question here at brainly. Below is Yoland's study:

<span>Yolanda is studying two waves. The first wave has an amplitude of 2 m, and the second has an amplitude of 3 m.
</span>
I think the answer is "She can use constructive interference to generate a wave with an amplitude of 1.5 m."

6 0

2 years ago

Read 2 more answers

Friction force equation

Sedaia [141]

It’s FF= μ•Fn
Ff stands for friction force
The weird symbol is your coefficient of friction which has no units
Fn stands for normal force

4 0

2 years ago

Technician A says that vehicle-to-vehicle communication results in fewer traffic collisions. Technician B says there are concern

Leto [7]

Answer:

Option C. Both technicians A and B are correct

Explanation:

Vehicle-to-vehicle communications consists of a wireless network where automobiles send messages containing operational information such as speed, location, direction of travel, braking, and loss of stability.

Technician A is correct, there will be fewer traffic collision because each driver will have enough information about traffic flow and such information will be properly managed since they have been known before hand.

By letting out information, such as your location, direction of traffic, etc, there is loss of privacy. This can lead to a security threat on the part of the users

4 0

2 years ago