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mars1129 [50]
3 years ago
7

Application

Physics
1 answer:
natulia [17]3 years ago
3 0

Answer:

\[0.900\hat{i}+0.600\hat{j}\,\text{N}\]

Explanation:

https://opentextbc.ca/universityphysicsv1openstax/chapter/5-7-drawing-free-body-diagrams/

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The distance from the sun to Earth would be
Alchen [17]

less than one light year!

Explanation:

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3 years ago
An object has a mass of 120 kg on the moon. What is the force of gravity acting on the object on the moon?
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m-mass \\ g-gravitational \ acceleration \\ G-the \ force \ of \ gravity \\\\ G=m*g \\\\ G=120*1.62 \\\\ \boxed{G=194.4N}
5 0
3 years ago
Read 2 more answers
A 15-kg bicycle carrying a 50-kg boy is traveling at a speed of 5 m/s. What is the KE of the bicycle and the boy?
vovangra [49]
Together as one moving package, their mass is (15 + 50) = 65 kg.

       Kinetic energy = (1/2) (mass) (speed)²

                               = (1/2) (65 kg) (5 m/s)²

                               =  (32.5 kg) (25 m²/s²)

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4 0
4 years ago
A man walks 400 m in the direction 45° north of east. Represent this vector graphically by
Marrrta [24]

Answer:

Explanation:

Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.

Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.

scale = \frac{length on drawing}{original length}

         = \frac{10}{400}

         = \frac{1}{40}

scale = 1:40

This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.

The man's direction is 45^{o} north of east.

The graphical drawing of the vector is herewith attached to this answer.

5 0
3 years ago
Acceleration on moon is approximately 1/6th of the Earth's; what would be the force of your egg drop package if dropped on the m
cricket20 [7]
  • Acceleration on earth=10m/s^2

Acceleration on moon:-

\\ \rm\Rrightarrow 10\dfrac{1}{6}=1.6m/s^2

Now

  • Mass=0.56kg

\\ \rm\Rrightarrow F=ma

\\ \rm\Rrightarrow F=0.56(1.6)

\\ \rm\Rrightarrow F=0.896N

8 0
3 years ago
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