Two charges that are separated by one meter exert 1-n forces on each other. if the magnitude of each charge is doubled, the forc
1 answer:
The electrostatic force between the two charges is
where q1 and q2 are the magnitudes of the two charges, and r the distance between them.
We can see from the formula that F is proportional to the product between the two charges:
so, if the magnitude of each charge is doubled, the new force will get a factor 4:
So, the new force will be 4 times the original force:
where q1 and q2 are the magnitudes of the two charges, and r the distance between them.
We can see from the formula that F is proportional to the product between the two charges:
so, if the magnitude of each charge is doubled, the new force will get a factor 4:
So, the new force will be 4 times the original force:
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Answer:
Explanation:
Acceleration is equal to the change in velocity over the change in time, or
where the change in velocity is final velocity minus initial velocity. Filling in:
Note that I made the backward velocity negative so the forward velocity in our answer will be positive.
Simplifying that gives us:
and then isolating the final velocity, our unknown:
3.0(6.0) = v + 3.0 and
3.0(6.0) - 3.0 = v and
18 - 3.0 = v so
15 m/s = v and because this answer is positive, that means that the car is no longer rolling backwards (which was negative) but is now moving forward.