Answer:
The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².
Explanation:
The centripetal acceleration is given by:
Where:
: is the tangential speed = 9.50 m/s
r: is the distance = 6.00 m
Hence, the centripetal acceleration is:
Therefore, the centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².
I hope it helps you!
Answer:
E = 1.24MeV
Explanation:
The photon travels at the speed of light, 3.0 × 
m/s, and given that its frequency = 1 picometer = 1.0 × 
m.
Its energy can be determined by;
E = hf
= (hc) ÷ λ
where E is the energy, h is the Planck's constant, 6.626 × 
Js, c is the speed of the light and f is its frequency.
Therefore,
E = (6.626 × × 3.0 × ) ÷ 1.0 ×
= 1.9878 × 
÷ 1.0 ×
E = 1.9878 × 
J
But, 1 eV = 1.6 × 
J. So that;
E = 
= 1242375 eV
∴ E = 1.24MeV
The energy of the photon is 1.24MeV.
<h2>Final velocity of man is -0.23 m/s.</h2>
Explanation:
Conservation of linear momentum :
When no external force acts on a system of several interacting particles, the total linear momentum of system is conserved.
Before the Throw ; Man mass (M₁) = 84.1 kg,
Velocity of Man (u₁) = 0 m/s
Book Mass(M₂) = 1.80 kg
Velocity of book (u₂)= 0 m/s
After the throw ; Man mass(M₁) = 84.1 kg
Velocity of Man(V₁) = ?
Book mass(M₂) = 1.80 kg
velocity of book(V₂) = 11.1 m/s
According to conservation of linear Momentum
Initial Momentum = Final Momentum
M₁u₁ +M₂u₂ = M₁v₁ + M₂v₂
84.1 x0 + 1.80 x0 = 84.1 x v₁ + 1.80 x 11.1
0 = 84.1 v₁ + 19.98
v₁ = -19.98 /84.1
= -0.23 m/s
final velocity of man is -0.23 m/s
Answer:
maybe:)
Explanation:
it really just depends on the subject and grade for me, I'm good in history and writing!
