Answer:
1317.4 m
Explanation:
We are given that
Angle=
Initial speed =
We have to find the horizontal distance covered by the shell after 5.03 s.
Horizontal component of initial speed=
Vertical component of initial speed=
Time=t=5.03 s
Horizontal distance =
Using the formula
Horizontal distance=
Horizontal distance=1317.4 m
Hence, the horizontal distance covered by the shell=1317.4 m
<span>Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles.
</span>2.39 moles Ne ( 6.022 x 10^23 atoms / mole ) = 1.44 × 10^24 atoms Ne
Answer: Infrared light
Explanation:
Infrared light is an electromagnetic radiation which has longer wavelength than visible light.
cool and faint objects are difficult to be detected using visible light.
Infrared light can pass through dust and clouds of gases. Thus, it is the best way to study the young stars hidden behind interstellar dust clouds.
Then the force of gravity between them would be quadrupled and so on but the gravitational force is inversely proportional to the square of the separation distance between the two interacting objects which makes more separation distance will result in weaker gravitational forces
Answer:
The mass of the solid cylinder is 
Explanation:
From the question we are told that
The radius of the grinding wheel is 
The tangential force is 
The angular acceleration is 
The torque experienced by the wheel is mathematically represented as

Where I is the moment of inertia
The torque experienced by the wheel can also be mathematically represented as

substituting values


So


So

This moment of inertia can be mathematically evaluated as

substituting values

=> 