Answer: For ideal machine efficiency = 1. Hence M.A = V. R. The V. R of an ideal machine and the practical machine is a constant or is the same for both
Answer:
wire 66.0 cm long carries a 0.750 A current in the positive direction of an x axis through a magnetic field $$\vec { B } = ( 3.00 m T ) \hat { j } ...
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R = 1.4GΩ.
The relation between the resistance and the resistivity is given by the equation R = ρL/A, where ρ is the resistivity of a given material, L is the length and A is the cross-sectional area of the material.
To calculate the resistance of a wire of L = 2m, ρ = 49x10⁴Ω.m and A = 0.7mm² = 0.7x10⁻³m² we have to use the equation R = ρL/A.
R = [(49x10⁴Ω.m)(2m)/0.7x10⁻³m²
R = 98x10⁴Ω.m²/0.7x10⁻³m²
R = 1.4x10⁹Ω = 1.4GΩ
Answer:
0.203 micro meter
Explanation:
for destructive interference that appearsblack, use the formula
2 t = m λ / u (where m = 0 1 2 3 ... is order of minima)
where t = tickness,
u is the ref index = 1.32
Wavelenth λ = 535×10^-9 meter
for t (minimum) m = 1 (as m=0 is ruled out as t>0)
t = 1× 535×10^-9/2×1.32
t (min) = 202.65×10^-9 meter
OR
t (min) = 0.203×10^-6 meter = 0.203 micro meter
Answer:
It traveled 24 centimeters
Explanation:
The displacement of the object is equal to the area under the velocity vs time graph.
We can split this graph into two shapes, a triangle and a rectangle. So the total area is:
A = ½bh + wh
A = ½ (4 s − 0 s) (4 cm/s) + (8 s − 4 s) (4 cm/s)
A = 8 cm + 16 cm
A = 24 cm