The mining-resource cycle determines the use of ore materials. Which step is not part of the cycle?
1 answer:
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Answer:
The frequency of the oscillation is 2.45 Hz.
Explanation:
Given;
mass of the spring, m = 0.5 kg
total mechanical energy of the spring, E = 12 J
Determine the spring constant, k as follows;
E = ¹/₂kA²
kA² = 2E
k = (2E) / (A²)
k = (2 x 12) / (0.45²)
k = 118.519 N/m
Determine the angular frequency, ω;
Determine the frequency of the oscillation;
ω = 2πf
f = (ω) / (2π)
f = (15.396) / (2π)
f = 2.45 Hz
Therefore, the frequency of the oscillation is 2.45 Hz.
Answer:
Explanation:
Given
Displacement is of Amplitude
i.e. , where A is maximum amplitude
Potential Energy is given by
Total Energy of SHM is given by
Total Energy=kinetic Energy+Potential Energy
Potential Energy is th of Total Energy
Kinetic Energy is of Total Energy
(c)Kinetic Energy is