Answer:
Explanation:
According to the property of a conductor, the entire charge will reside on the outer surface of the conductor, there is no charge on the inner side of the conductor. As the uncharged metal ball touches the inner surface of the conductor, it does not attain any charge as the inner side of the conductor has no charge.
So option (c) is correct.
Answer:
option B. Limestone
<em>h</em><em>o</em><em>p</em><em>e</em><em>f</em><em>u</em><em>l</em><em>l</em><em>y</em><em>,</em>
<em>Z</em><em>a</em><em>r</em><em>a</em><em>♡</em>
Kinetic Energy is defined by Ke=1/2mv^2. Plug in and solve for v.
2,000 = 1/2(1000)(v)^2
4=(v)^2
v=2 m/s
The car must move at 2 m/s to have a Ke of 2,000 Joules.
The time taken before the two soccer players are 24.7 m apart is 3 seconds.
Velocity of Jane relative to marry is 4.4 m/s in y-direction and 6.95 m/s in x direction.
The distance between Jane and Mary after 4.08 seconds is 33.58 m.
<h3>
Resultant velocity of Mary and Jane</h3>
Vertical component of the velocity;
Jane: Vy1 = V sinθ
Vy1 = 5.07 m/s x sin(60.2)
Vy1 = 4.4 m/s
Horizontal components of the velocity;
Jane: Vx1 = V cos θ
Vx1 = 5.07 m/s x cos60.2
Vx1 = 2.52 m/s
mary: Vx2 = 4.43 m/s
total horizontal components of the velocity = 4.43 m/s + 2.52 m/s = 6.95 m/s
<h3>Resultant velocity</h3>
V = √Vy² + Vx²
V = √(4.4² + 6.95²)
V = 8.23 m/s
<h3>Time taken before they are 24.7 m apart</h3>
t = 24.7 m / 8.23 m/s
t = 3 seconds
Velocity of Jane relative to marry is 4.4 m/s in y-direction and 6.95 m/s in x direction.
<h3>Distance between Jane and Mary after 4.08 seconds</h3>
d = vt
d = 8.23 m/s x 4.08 s
d = 33.58 m
Learn more about relative velocity here: brainly.com/question/17228388
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Answer
-The magnitude of acceleration during the fall is greater
