Answer:
The volume of the figure is ![(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of the figure is equal to the volume of the cone minus the volume of the square pyramid
step 1
Find the volume of the cone
The volume of the cone is equal to
we have
----> the diagonal of the square base of pyramid is equal to the diameter of the cone
substitute
step 2
Find the volume of the square pyramid
The volume of the pyramid is equal to
where
B is the area of the base
h is the height of the pyramid
we have
substitute
step 3
Find the volume of the figure
![\frac{1}{6}\pi (l)^{3}\ units^{3}-\frac{1}{3}l^{3}\ units^{3}=(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cpi%20%28l%29%5E%7B3%7D%5C%20units%5E%7B3%7D-%5Cfrac%7B1%7D%7B3%7Dl%5E%7B3%7D%5C%20units%5E%7B3%7D%3D%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Answer:
Monday:
<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><em>3</em>
<em>Tablespoon</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><u><em>3</em><em>0</em></u>
<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><u><em>7</em><em>5</em></u>
Wednesday
<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><u><em>1</em><em>.</em><em>1</em><em>2</em></u>
<em>Tablespoons</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em>
<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><em>2</em><em>8</em>
The original number to the nearest tenth is 23.8
