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3 years ago

What is 1.3 divided by 4.7

Mathematics

1 answer:

Savatey [412]3 years ago

7 0

Answer:

0.27659574

Step-by-step explanation:

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Show all your work to receive credit!<br><br> What is m∠KNLm∠KNL?<br><br> Question 2 options:

Nataly_w [17]

3(x+14) i think thats it

8 0

3 years ago

Ajutați-mă va rog frumos!

Mashutka [201]

Answer:

e 3323234352

Step-by-step explana tion:

3t5434436t456r23

6 0

3 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

4 years ago

Help needed! Trying to get answer

Angelina_Jolie [31]

1/27 and (3^15)*(3^-18)

4 0

3 years ago

I will mark brainliest

yulyashka [42]

Angles a and e! they’re alternate interior angles, therefore they are congruent.

8 0

3 years ago