The number of ways there are to move from (0, 0) to (7, 7) in the coordinate plane with movements of only one unit right or one unit up accordingly is; 49 while that such that y =x is; 7.
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How many ways are there to get from (0, 0) to (7, 7) in the coordinate plane with pmovements of only one unit right or one unit up?</h3>
It follows from the task content that the movement intended on the coordinate plane is; from (0, 0) to (7, 7).
The number of ways to move such that movements of only one unit right or one unit up is; 7 × 7 = 49.
The number of ways for which y= x is therefore is; 7 as the movement is diagonal.
Read more on coordinate plane;
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Argument
Let the second angle = x
Let the first angle = 2x
Let the third angle = x + 64
Substitute and Solve
x + 2x + x + 64 = 180 Collect the like terms on the left.
4x + 64 = 180 Subtract 64 from both sides.
4x = 180 - 64
4x = 116 Divide by 4
x = 116 / 4
x = 29
Conclusion
x = 29
2x = 58
x + 64 = 93 I'm leaving you with the problem of checking this out.
Answer
The first angle = 58
The second angle = 29
The Third angle = 93
Answer:
168
Step-by-step explanation:
60+16+8 is 84
84 times 2 is 168
Mark me as brainliest if this helps!
Step-by-step explanation:
the perimeter is
2×length + 2×width = 86
length = 3×width
now we use the second equation as variable identity in the first equation :
2×3×width + 2×width = 86
6×width + 2×width = 86
8×width = 86
width = 86/8 = 43/4 = 10.75 cm
length = 3×width = 3×10.75 = 32.25 cm
