Hello!
* First Step: to know Avogrado's Law
We know that by the Law of Avogrado, for each mole of substance we have 6.02*10²³ atoms, if:
** Second Step: to know the molar mass of the solute
The molar mass of of magnesium = 24.30 g/mol
*** Third step: make the ratio mass / mol with atoms
1 mol we have 6.02*10²³ atoms
1 mole of Mg we have 24.30 g
Then we have:
24.30 g ------------- 6.02*10²³ atoms
x ----------------------- 6.98*10^24 atoms
multiply cross
I Hope this helps, greetings ... DexteR! =)
Answer:
24.66%
Explanation:
To find the percent of water (H2O) in the following compound: Zn3(PO4)2. 7H2O
The atomic mass of the elements are as follows:
Zn = 65g/mol
P = 31g/mol
O = 16g/mol
H = 1g/mol
Hence, molar mass of the compound is as follows:
65(3) + {31 + 16(4)} 2 + 7{1(2) + 16}
195 + 95(2) + 7(18)
195 + 190 + 126
511g/mol
Molar mass of 7H2O
= 7(18)
= 126g/mol
Hence, the percent of H2O in the compound is:
Molar Mass of 7H2O/molar mass of compound × 100
= 126/511 × 100
= 0.2466 × 100
= 24.66%
The answer would be B
Explanation: There is more Newton force pushing it and since it's on a flat surface it moves more than a higher kg weight block.
Answer:
Because the value of K is huge.
Explanation:
The tautomer is a kind of isomer in which exist an equilibrium between a ketone and an enol, or between an aldehyde and an enol. So, in the enolization, the ketone is the reactant and the enol is the product.
The equilibrium reaction can be characterized by an equilibrium constant, which is the ratio of the concentration of the products by the concentration of the reactants.
Because the constant K is extremely large (10¹³) we can conclude that the concentration of the product will be greater than the concentration of the reactant, in the equilibrium. It means that the concentration of the enol will be greater.
So, the ketone is unstable and forms in a great amount the more stable product, the enol.
Answer:
Equivalence point titration
Explanation: Equivalent point: point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution. At the equivalence point in an acid-base titration, moles of base = moles of acid and the solution only contains salt and water.
