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katovenus [111]
4 years ago
15

K for enolization of 2,4-cyclohexadienone is about 1013. Explain why the enol is so much more stable than the keto tautomer.

Chemistry
1 answer:
torisob [31]4 years ago
4 0

Answer:

Because the value of K is huge.

Explanation:

The tautomer is a kind of isomer in which exist an equilibrium between a ketone and an enol, or between an aldehyde and an enol. So, in the enolization, the ketone is the reactant and the enol is the product.

The equilibrium reaction can be characterized by an equilibrium constant, which is the ratio of the concentration of the products by the concentration of the reactants.

Because the constant K is extremely large (10¹³) we can conclude that the concentration of the product will be greater than the concentration of the reactant, in the equilibrium. It means that the concentration of the enol will be greater.

So, the ketone is unstable and forms in a great amount the more stable product, the enol.

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PLEASE HELP! WILL GIVE BRAINLIEST:
Ad libitum [116K]

2.45 °C

From the Ideal gas law (Combined gas law)

PV/T = P'V'/T' .....eq 1

Where:

P - initial pressure

V - initial volume

T - initial temperature

P' - final pressure

V' - final volume

T' - final temperature.

To proceed we have to make T the subject from eq.1

Which is, T = P'V'T/PV.......eq.2

We have been provided with;

Standard temperature and pressure (STP)

P = 760 mm Hg (SP - Standard Pressure)

T = 273.15 K (ST - Standard Temperature)

V = 62.65 L

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V' = 78.31 L

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T' = 275.60 K

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>>>>> Answer

Have a nice studies.

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2 years ago
At 82K, a gas has a volume of 4.60L. What would be the volume of the gas at 70K?
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Answer:

V₂ = 4.0L

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Decreasing temperature => Decreasing Volume (Charles Law)

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Volume at lower temp = 4.6L(70K/82K) = 4.0L ... Using (82K/70K) would give a larger volume => contrary to temperature effects on gas volumes when pressure and mass are kept constant.

Pressure effects on Gas Volumes:

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Given a gas volume of 4.60L at 760mmHg, what is volume at 848mmHg?

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