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katovenus [111]
3 years ago
15

K for enolization of 2,4-cyclohexadienone is about 1013. Explain why the enol is so much more stable than the keto tautomer.

Chemistry
1 answer:
torisob [31]3 years ago
4 0

Answer:

Because the value of K is huge.

Explanation:

The tautomer is a kind of isomer in which exist an equilibrium between a ketone and an enol, or between an aldehyde and an enol. So, in the enolization, the ketone is the reactant and the enol is the product.

The equilibrium reaction can be characterized by an equilibrium constant, which is the ratio of the concentration of the products by the concentration of the reactants.

Because the constant K is extremely large (10¹³) we can conclude that the concentration of the product will be greater than the concentration of the reactant, in the equilibrium. It means that the concentration of the enol will be greater.

So, the ketone is unstable and forms in a great amount the more stable product, the enol.

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What volume of a 0.3300M solution of sodium hydroxide would br ruired to titrate 15.00 mL of 0.1500 M oalic Acid?
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Answer:

3.41 mL

Explanation:

At equivalence point  from the reaction given,

Moles of Oxalic\ Acid = 2 × Moles of NaOH

Considering

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After careful deliberation, I took the opportunity to find the answers for you.

Answers: 
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3) _1_Fe + _2_HBr -> _1_H2 + _1_FeBr2
5) _2_NaOH + _1_ H2SO4 -> _1_Na2SO4 + _2_H2O
7) _2_N2O -> _2_N2 + _1_ O2
9) _1_P4O6 + _2_O2 -> _1_P4O10
11) _2_Mg + _2_CH3COOH -> _2_Mg(CH3COO)2 + _1_H2
13) _2_Al3 + _18_HCl -> _9_H2 + _6_AlCl3
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17) _2_NH3 -> _1_N2 + _3_H2
19) _2_SO2 + _1_O2 -> _2_SO3

DONE! *breathes heavily* Alright, after like 30 minutes, these are the answers for your problem.

Hope this helps! :)
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