Answer:
1.930 * 10⁻⁹ mg of Mn⁺² are left unprecipitated.
Explanation:
The reaction that takes place is:
Mn⁺² + S⁻² ⇄ MnS(s)
ksp = [Mn⁺²] [S⁻²]
If the pksp of MnS is 13.500, then the ksp is:
From the problem we know that [S⁻²] = 0.0900 M
We use the ksp to calculate [Mn⁺²]:
3.1623*10⁻¹⁴= [Mn⁺²] * 0.0900 M
[Mn⁺²] = 3.514 * 10⁻¹³ M.
Now we can calculate the mass of Mn⁺², using the volume, concentration and atomic weight. Thus the mass of Mn⁺² left unprecipitated is:
3.514 * 10⁻¹³ M * 0.1 L * 54.94 g/mol = 1.930 * 10⁻¹² g = 1.930 * 10⁻⁹ mg.
Answer:
acid is corrosive in nature
acid changes blue litmus to red
acid reacts with base to produce salt and water
The molar mass and the mass of the substance give the moles of the substance. The 10-gram sample of neon (Ne) has the fewest atoms. Thus, option b is correct.
<h3>What are moles?</h3>
Moles of the substance are the ratio of the molar mass and the mass of the substance. The moles of each atom with respect to the Avagadro's number (Nₐ) is given as,
Moles = mass ÷ molar mass
- Moles of carbon (C) = 10 ÷ 12
= 0.83 Nₐ atoms
- Moles of neon (Ne) = 10 ÷ 20
= 0.5 Nₐ atoms
- Moles of fluorine (F) = 10 ÷ 19
= 0.52 Nₐ atoms
- Moles of nitrogen (N) = 10 ÷ 14
= 0.7 Nₐ atoms
- Moles of oxygen (O) = 10 ÷ 16
= 0.63 Nₐ atoms
Therefore, option b. 10 gm neon has the fewest atoms.
Learn more about moles here:
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Answer:
it will melt
Explanation:
because the heat will observe it and melt
In the given situation, the reaction is-
NO + H2 ↔ Products
The rate of the reaction can be expressed (in terms of the decrease in the concentration of the reactants) as-
Rate = -dΔ[NO]/dt = -dΔ[H2]/dt
Now, if the concentration of NO is decreased there will be fewer molecules of the reactant NO which would decrease the its collision with H2. As a result the rate of the forward reaction would also decrease.
Ans) A decrease in the concentration of nitrogen monoxide decreases the collisions between NO and H2 molecules. the rate of the forward reaction then decreases.
