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dalvyx [7]
3 years ago
8

“Na2SO3” represents sodium sulfite.What does the 4 mean in the formula 4Na2SO3?

Chemistry
2 answers:
Strike441 [17]3 years ago
6 0

The mass of substance which consists the equal number of particles as 12 grams of Carbon-12 is said to be mole.

For example:

The balanced chemical equation for production of water from hydrogen and oxygen is:

2H_2(g) + O_2(g) \rightarrow 2H_2O(l)

That means 2 moles of H_2 reacts with 1 mole of O_2 to give 2 moles of  H_2O.

The given formula is 4Na_2SO_3.

Hence, 4 represents the number of moles in 4Na_2SO_3 formula that is 4 moles of Na_2SO_3.

The number of atoms of sodium, Na in 4Na_2SO_3 is:

4 \times 2 = 8

The number of atoms of sulfur, S in 4Na_2SO_3 is:

4 \times 1 = 4

The number of atoms of oxygen in, O in 4Na_2SO_3 is:

4 \times 3 = 12

Masteriza [31]3 years ago
3 0
You would find four put in front of the compound in an equation.  This is to indicate that there are four times more moles in the reaction than there is in the specie that has no number in front of it in the reaction.

  
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If 5.00 mL of 1.00 M HCl is used to titrate the hydroxide ion produced by a piece of Sodium, What mass of Sodium is used in gram
suter [353]

Answer:

Explanation:

Equation of the reaction:

NaOH + HCl --> NaCl + H2O

Volume of HCl = 5 ml

Molar concentration = 1 M

Number of moles = molar concentration * volume

= 1 * 0.005

= 0.005 mol of HCl

By stoichiometry, 1 mole of HCl completely neutralizes 1 mole of NaOH

Therefore, number of moles of NaOH = 0.005 mol

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

NaOH --> Na+ + OH-

Mass = molar mass * number of moles

= 40 * 0.005

= 0.2 g of Na+

6 0
3 years ago
Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4 What volume of 1.45 M Ca(OH)2 is needed to react with 25.0 moles of H2SO4?
Shkiper50 [21]

Answer:

We need 17.2 L of Ca(OH)2

Explanation:

Step 1: Data given

Concentration of Ca(OH)2 = 1.45 M

Moles of H2SO4 = 25.0 moles

Step 2: The balanced equation

Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4

Step 3: Calculate moles Ca(OH)2

For 1 mol Ca(OH)2 we need 1 mol H2SO4 to produce 2 moles H2O and 1 mol CaSO4

For 25.0 moles H2SO4 we'll need 25.0 moles Ca(OH)2 to produce 50 moles H2O and 25.0 moles CaSO4

Step 4: Calculate volume of Ca(OH)2

Volume Ca(OH)2 = moles Ca(OH)2 / concentration Ca(OH)2

Volume Ca(OH)2 = 25.0 moles / 1.45 M

Volume Ca(OH)2 = 17.2 L

We need 17.2 L of Ca(OH)2

3 0
3 years ago
Find the value of 6 +<br>6 +<br>6 + 16 + vo​
AVprozaik [17]

Answer:

6

Explanation:

the value is 6 because its an even number

7 0
2 years ago
What energy is required to remove the remaining electron from singly ionized helium?
skelet666 [1.2K]

To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy.

The amount of energy required by an isolated, gaseous molecule in the electronic state of the ground to absorb in order to discharge an electron and produce a cation has been known as the ionization energy. The amount of energy required for every atom in a mole to drop one electron is most often given as kJ/mol.

Anything that causes electrically neutral atoms and molecules to gain or lose electrons in order to become electrically charged atoms as well as molecules .

Therefore, the "To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy."

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brainly.com/question/14135172

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3 0
1 year ago
What does a metal's position in an activity series indicate about the chemical properties of that particular metal?
Fed [463]
The closer to the top the metal is in the list, the more active the metal is and the stronger a reducing agent the metal is. When two different metals are involved in a redox reaction, the metal higher in the list will be oxidized and give up electrons that will reduce the cation of the less active metal.
3 0
2 years ago
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