Answer:
50 micro mol/min
Explanation:
So, we have the following parameters which are going to help us in solving this particular Question or problem;
=> For the wild type enzyme, the value for the Maximum velocity = 100 micromol/min.
=> For the mutant type enzyme, the value for the Maximum velocity = 1 micromol/min.
So, we can determine or calculate the value for the initial velocity for each of the enzyme type by using the formula below;
Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.
Therefore, for the wild type enzyme; the Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.
Initial velocity =( 10mM × 100micromol/min) ÷ ( 10mM + 10 mM ) = 50 micro mol/min.
Initial velocity for the wild type enzyme = 50 micro mol/min.
The primary difference between organic vs. inorganic compounds is that organic compounds always contain carbon while most inorganic compounds do not contain carbon
Answer:
the three domains are Eukarya Archae and Eubacteria
Explanation:
an example of Eukarya is plants and animals
an example of Archae is methanogens
an example of bacteria is bacteria such as e.coli
Answer:
Glucose
Explanation:
Because when the plants have waste or produce they will make glucose.
X is mathematically an unknown.
