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3 years ago

Solve for the values of x for each of the following exponential equations and inequalities.

Mathematics

1 answer:

lilavasa [31]3 years ago

6 0

Answer:

2−x

8^{2-x}=8^{1/3}8

2−x

1/3

2-x=\dfrac{1}{3}2−x=

x=\dfrac{5}{3}x=

(\dfrac{1}{2})^{x}<\dfrac{1}{8}(

)

(\dfrac{1}{2})^{x}<(\dfrac{1}{2})^{3}(

)

x>3x>3

5^x=25^{x-2}5

=25

x−2

25^{x/2}=25^{x-2}25

x/2

=25

x−2

\dfrac{x}{2}=x-2

=x−2

\dfrac{x}{2}=2

x=4x=4

3^{x+2}\geq273

x+2

≥27

3^{x+2}\geq3^33

x+2

≥3

x+2\geq3x+2≥3

x\geq1x≥1

4^{3x}=8^{x-1}4

x−1

2^{6x}=2^{3x-3}2

3x−3

6x=3x-36x=3x−3

3x=-33x=−3

x=-1x=−1

Step-by-step explanation:

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If paul puts 300 dollars in a saving account that earns 3% interest how much interest will he earn after 2 years?

Evgesh-ka [11]

Answer:

<h2> $\boxed{18 \: dollars}$ </h2>

Step-by-step explanation:

Principal ( P ) = $ 300

Rate ( R ) = 3%

Time ( T ) = 2 years

Now, let's find the simple Interest:

I = $\mathsf {\frac{PTR}{100} }$

$\mathsf{ = \frac{300 \times 2 \times 3}{100} }$

$\mathsf{ = \frac{1800}{100} }$

$\mathsf{ = 18}$

Extra information:

Simple Interest

In our daily life when we borrow a sum of money either from a moneylender or from any financial company, we have to pay the money back by adding with extra sum of money. This borrowed money is called principal. The extra money to be paid for the borrowing money is called interest , which is paid after certain duration in certain rate. At last, the borrowed money should be paid back along with interest which is called amount.

Interest is based on three factors : Principal ( P ) , Rate of interest ( R ) and Time ( T ). While computing the interest, the rate must be in percent and time in years.

$\mathsf{ \: simple \: interest \: = \frac{PTR}{100} }$

On simplifying

$\mathsf{p = \frac{I \times 100}{T \times R} }$

$\mathsf{t = \frac{I \times 100}{P \times R} }$

$\mathsf{r = \frac{I \times 100}{P \times T}}$

And from the definition,

Amount ( A ) = Principal ( P ) + Interest ( I )

Principal ( P ) = Amount ( A ) - Interest ( I )

Interest ( I ) = Amount ( A ) - Principal ( P )

Hope I helped!

Best regards!

4 0

3 years ago

Read 2 more answers

HURRY PLEASE I NEED HELP

pashok25 [27]

The reasonable value for the range of the given function is: A. 75.

<h3>What of the Range of a Function?</h3>

The range of a function is the output that a corresponding input value would give as a relation.

In this scenario, the grade you get is a function of number of hours you study. Range is the grade (output), while the domain is hours of study (input).

The given possible range values in the options are, 75, 1.25, -30, 1/2.

A reasonable value of a a grade cannot be a negative number, neither can it be 1.25, nor 1/2.

Therefore, the reasonable value of the range is: A. 75.

Learn more about the range of a function on:

brainly.com/question/7644636

#SPJ1

5 0

2 years ago