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Artist 52 [7]
2 years ago
10

Place the items in order from lowest to highest degree of internal organization

Biology
1 answer:
exis [7]2 years ago
7 0
Organ System, Organ coll, tissue
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List 2 organelles found in an animal cell and explain how those 2 organelles benefit the cell.
pav-90 [236]

Answer:

I chose nucleus and the mitochondria

Explanation:

The nucleus is particularly important among eukaryotic organelles because it is the location of a cell's DNA. Two other critical organelles are mitochondria and chloroplasts, which play important roles in energy conversion and are thought to have their evolutionary origins as simple single-celled organisms.

Have a great day! :)

6 0
2 years ago
¿Qué relación tiene el trasporte de las sustancias a través de la membrana celular con la homeóstasis?
erma4kov [3.2K]

Answer:

El transporte celular ayuda a las células a mantener la homeostasis manteniendo rangos normales dentro de todas las células de un organismo.

3 0
3 years ago
Please help
Anettt [7]

Answer:

Heat

Explanation:

In almost all the energy conversion process some of energy is lost in the form of heat.

3 0
2 years ago
Please help meeeeee
Brums [2.3K]
Sorry i needed the points... good luck tho
7 0
2 years ago
Read 2 more answers
Sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous
Pavel [41]

Answer:

6,25%

Explanation:

Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:

Parents: Aa X Aa

Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)

Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:

A x A = 1/4 = 25%

A x a = 1/4 = 25%

a x A = 1/4 = 25%

a x a = 1/4 = 25%

The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:

1/4 × 1/4 = 1/16 = 0.0625 = 6.25%

It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.

6 0
3 years ago
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