The length of one leg of the right triangle is 5√10
<h3>How to find the leg of a right triangle?</h3>
The leg of a right triangle can be found as follows;
Therefore, using trigonometric ratios,
sin 45 = opposite / hypotenuse
sin 45 = x / 10√5
1 / √2 = x / 10√5
cross multiply
10√5 = x√2
divide both sides by √2
x = 10√5 / √2
x = 10√5 / √2 × √2 / √2
x = 10√10 / 2 = 5√10
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Answer:
1 out of 2
Step-by-step explanation:
You already took out on tile from the bag, yellow. Now you are left with 2, meaning that it is a 50/50 chance of you pulling out the orange tile
Answer:
1/5 (x-3)
Step-by-step explanation:
1/5x -3/5
1/5 (x-3)
Radical 2 = 1.4 So 1.4 * 6 = 8.4
a^2 + b^2 = c^2
8.4^2 + 8.4^2 = square root of c
70.56 + 70.56 = 141.12 ≈ 141
Then you must find the square root of 141 which is 11.874 ≈ 11.9
Side a = 8.4
Side b = 8.4
Side c = 11.9
Answer:
1. -2, -4
2. 7, ½
3. -2, -3
Step-by-step explanation:
1) -x² - 6x - 8 = 0
x² + 6x + 8 = 0
x² + 4x + 2x + 8 = 0
x(x + 4) + 2(x + 4) = 0
(x + 2)(x + 4) = 0
x = -2 , -4
2) 2x² - 15x + 7
2x² - 14x - x + 7 = 0
2x(x - 7) - (x - 7) = 0
(2x - 1)(x - 7) = 0
x = ½, 7
3) 3x² + 15x + 18 = 0
x² + 5x + 6 = 0
x² + 3x + 2x + 6 = 0
x(x + 3) + 2(x + 3) = 0
(x + 3)(x + 2) = 0
x = -2, -3
