Si el punto (5,0) está en una gráfica, żes (5,0)

-13/28+17/20 give answer as a reduced proper or improper fraction

Kay [80]

13/28+17/20=−13/28+17/20=27/70

6 0

3 years ago

A quadratic function and an exponential function are graphed below. Which graph most likely represents the exponential function?

Cloud [144]

Answer:

Step-by-step explanation:

The correct answer is the second one. The function g(x) is increasing "faster" than f(x), and this is true of exponential functions in general. This should make sense if you're familiar with the concept of limits at infinity.

6 0

3 years ago

1. (10 marks) A study of the home purchasing habits of Canadians in show homes found the following interesting facts. The probab

Butoxors [25]

Answer:

$1 a. P(X=1)=0.3809\\\\b. P(X\geq 1)=0.5721\\c. \mu_x=0.81, \ \ \ \sigma_x=0.7371\\d. Increase \ n$

$2.a. 0.2438\\b. 0.6227\\c. \mu_8=17.6, \ \sigma_8=4.1952$

Step-by-step explanation:

The purchase of a house has binomial distribution with p=9% and n=9

a. To find the probability of one house being sold:

$p(x)={n\choose x}p^x(1-p)^{n-x}$

The value of x is 1:

$p(x)={n\choose x}p^x(1-p)^{n-x}\\\\\\P(X=x)={9\choose 1}0.09(1-0.09)^8\\\\=0.3809$

Hence, the probability that one house is sold that day is 0.3809

b.The probability of at least one house is the same as the 1 minus the probability that no house was sold:

$p(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 1)=1-P(X=0)\\\\=1-{9\choose 0}0.09^0(0.91)^9\\\\=1-0.4279\\\\=0.5721$

Hence,the probability that at least one house is sold that day is 0.5721

c. The mean of a binomial distribution is the product of the number of events times the probability of success=np

From a above, n=9 and p=0.09:

$\mu_x=np, \ n=9 , \ p=0.09\\\\=9\times 0.09\\\\=0.81$

#The standard deviation is calculated as np(1-p):

$\sigma_x=np(1-p),\ n=9, p=0.09\\\\=9\times 0.09\times 0.91\\\\=0.7371$

Hence, the distribution has a mean of 0.81 and a standard deviation of 0.7371

d. Given that the probability of success is low, the overall successful events can only be increased by increasing the sample size, say n should be increased to 1000.

2. a.Given a Poisson distribution with mean=2.2

-The probability in a Poisson distribution is expressed as:

$P(x;\mu)=\frac{e^{-\mu}\mu^x}{x!}$

The probability of one person showing up is calculated as:

$P(x;\mu)=\frac{e^{-\mu}\mu^x}{x!}\\\\P(1,2.2)=\frac{e^{-2.2}2.2^1}{1!}\\\\=0.2438$

Hence , the probability that exactly one person shows up during a 1-hour period is 0.2438

b. the probability that at most 2 people will show up during a 1-hour period is calculated as:

$P(x;\mu)=\frac{e^{-\mu}\mu^x}{x!}\\\\P(x\leq2 ;\mu)=P(x=0;\mu)+P(x=1;\mu)+P(x=2 ;\mu)\\\\=\frac{e^{-2.2}2.2^0}{0!}+\frac{e^{-2.2}2.2^1}{1!}+\frac{e^{-2.2}2.2^2}{2!}\\\\=0.1108+0.2438+0.2681\\\\=0.6227$

Hence,the probability that at most 2 people will show up during a 1-hour period is 0.6227

c. The mean and variance of a Poisson distribution is equal:

$E(X)=\mu=Var(X)=\sigma^2, \mu=2.2\\\\8E(X)=8(2.2)=\mu_8\\\\\mu_8=17.6\\\\V(X)=\sigma^2=17.6\\\\\sigma=4.1952$

Hence the mean after 8 hrs is 17.6 and the standard deviation will be 4.1952

6 0

3 years ago

Help with this one!!!<br><br><br> Show steps pls :)

andrew11 [14]

•Convert 20% to decimal.
To convert a number to a decimal, divide by 100
20 divided by 100= 0.2
•$171.70 x 0.2=34.34
•171.70 + 34.34=206.04

The amount of the markup is $34.34

I hope I did this right and it helps, calculating markup becomes easier to do when you get more familiar with it.

4 0

3 years ago

Read 2 more answers

HELP ME PLSS !!!!!!!!!!!!!!!

FrozenT [24]

Answer:

x<8

Step-by-step explanation:

Had that same question

3 0

2 years ago

Read 2 more answers