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2 years ago

What is the equation of a line with slope 2 and intercept 4?

Mathematics

2 answers:

xz_007 [3.2K]2 years ago

7 0

Answer:

Y = 2x + 4

Step-by-step explanation:

The slope-intercept equation is y = mx + b

M = slope and b = intercept

To make the equation all you have to do is insert the numbers.

So:

Since the slope is 2:

Y = 2x + b.

Since the intercept is 4

Y = 2x + 4.

Greeley [361]2 years ago

3 0

The linear equation/slope intercept form is y=mx+b

M is the slope and b is the y-intercept.

So the equation would be: y=2x+4

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A ball is thrown into the air and its position is given by h ( t ) = − 6.3 t 2 + 53 t + 24 where h is the height of the ball in

nordsb [41]

Answer:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

Step-by-step explanation:

For this case we have the following function:

$h(t) = -6.3t^2 +53 t+24$

In order to maximize this function we need to take the first derivate respect the time and we have:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

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What is the area of this figure

solmaris [256]

Answer:

Step-by-step explanation:

3(3) = 9

15-3=12

12(9)= 108

7(9)=63

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Step-by-step explanation:

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JulsSmile [24]

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