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2 years ago

Please help me please I’m begging you this is an assessment grade

Mathematics

1 answer:

Vladimir79 [104]2 years ago

6 0

Answer:

-2 , 4

Step-by-step explanation:

-2 + 4 = -2

-2 * 4 = -8

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A small hexagon was graphed on a coordinate plane. By what scale factor was the hexagon dilated to create the larger hexagon?

suter [353]

Consider the point where the hexagons meet the positive half of the y axis.

The inner hexagon meets the axis at $y=4$ , whereas the outer hexagon meets the axis at $y = 6$

So, we're looking for a dilation constant $k$ such that

$4k = 6$

So, solving by k we have

$k = \dfrac{6}{4} = \dfrac{3}{2}$

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3 years ago

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Vertical analysis (common-size) percentages for Vallejo Company’s sales, cost of goods sold, and expenses are listed here.

dybincka [34]

Cost of goods sold - expenses = net income
do this for each year and compare.

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3 years ago

How to find the line of reflection between two points?

eimsori [14]

Use the midpoint formula.
(x1+x2)/2 , (y1+y2)/2
Then you should be able to find the reflection line based on where the middle of the two points are.

3 0

3 years ago

SOLVE FOR X PLEASEE HELP

Ivenika [448]

To solve this, you will have to set up your equation as fractions:

X is to 4 as 4 is to 4+3, or 7

X/4 = 4/7

You will then cross multiply

7x = 4•4
7x = 16

Divide.

X = 2.285714...

Round to the nearest hundredth.

2.29

3 0

3 years ago

WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)

IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0

3 years ago