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choli [55]
3 years ago
8

0÷0 what is the answer​

Mathematics
2 answers:
navik [9.2K]3 years ago
6 0
100
—————————————————
lbvjy [14]3 years ago
3 0

Answer:

This answer is 0

Step-by-step explanation:

The reason the answer is 0 is besause the 0 can go 0 times in 0

kind of hard to explain

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Find C.<br> Round to the nearest tenth
andre [41]

Answer:

Step-by-step explanation:

c^2=a^2+b^2-2abcosC

cosC= (a^2+b^2-c^2)/(2ab)

C=arccos[(a^2+b^2-c^2)/(2ab)]

C=arccos(90^2+55^2-50^2)/(2(90)55)

C=arccos(8625)/(9900)

C=29.4 degrees

5 0
3 years ago
Is a square a special parallelogram
Debora [2.8K]

idk what a special parallelogram is but a square is most definitely a parallelogram :)

Answer:

a square is a quadrilateral but<em><u> is also a parallelogram</u></em>,rectangle and a rhombus

Step-by-step explanation:

a square is many things such as a parallelogram, a rectangle, and a rhombus.

it is a quadrilateral with all right angles and all equal sides

×║hope this helps║×

6 0
3 years ago
How do you solve for M in the formula?<br>Give Steps Please!​
Murljashka [212]

Answer:

m = \frac{gs^{2}}{10}

Step-by-step explanation:

g = 10(\frac{m}{s^{2} })

simplify:

g = \frac{10m}{s^{2}}

multiply both sides by s²:

gs² = 10m

divide both sides by 10:

m = \frac{gs^{2}}{10}

7 0
3 years ago
In ΔUVW, u = 5.8 inches, ∠W=77° and ∠U=87°. Find the length of v, to the nearest 10th of an inch.
natali 33 [55]

Answer:

1.6

Step-by-step explanation

You can use the angles given to figure out the degree of the angles given and then with that you set up your equation as v divided by Sin(16) is equal to 5.8 divided by sin(87) and cross multiply.

After you cross multiply you should get approximately 1.5987 is equal to v times sin(87)

you then fin out the approximation of sin(87) which should be around 0.9986 and divide both sides by 0.9986 so v is alone and your answer comes out to be v = 1.6

6 0
3 years ago
Please help will mark Brainly
Brilliant_brown [7]

Answer:


Step-by-step explanation:

This is not a linear relationship, it doesn't have a set increase or uniform slope and it seems more like an exponential or quadratic curve to me when I graph it. As you can see you cant draw a straight line through the data points so it cannot be a linear relationship.

7 0
3 years ago
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