Answer:
A
Step-by-step explanation:
AB ll CD
what grade r u in btw ?
Answer:
Volume = ⅓n²(n-1) or ⅓(n³ - n²)
Step-by-step explanation:
Given
Solid Shape: Right pyramid
Edge= n units
Height= n - 1 units
Required
Volume of the pyramid
The volume of a right pyramid is
Volume = ⅓Ah
Where A represents the area of the base
h represent the height of the pyramid
Since it has a square base;
The area is calculated as follows
Area, A = edge * edge
A = n * n
A = n²
Recall that
Volume = ⅓Ah
Substitute n² for A and n - 1 for h
The expression becomes
Volume = ⅓ * n² * (n - 1)
Volume = ⅓n²(n-1)
The expression can be solved further by opening the bracket
Volume = ⅓(n³ - n²)
Y intercept is (0,-7). slope is 2.
Change the function to y=mx+b format first. m=slope and plug in 0 as x to get y intercept.
Let x be the original radius. Given that a semicircle will have an arc length of half of a circumference and C=2pr, the arc length will be just pr.
Now the difference of arc is then going to be:
p(6+x)-px
p(6+x-x)
6p inches
So the arc will be 6p inches longer. Or if you wish to approximate...
≈18.85 inches
