Answer:
The answer is D.8 sulfer atoms and 16 oxygen atoms
Explanation:
Answer:
Molecular formula = C₄H₆As₆Cu₄O₁₆
Explanation:
Given data:
Empirical formula = C₂H₃As₃Cu₂O₈
Molar mass of compound = 1013 g/mol
Molecular formula = ?
Solution:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass of C₂H₃As₃Cu₂O₈ is 506.897 g/mol
by putting values.
n = 1013 / 506.897
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (C₂H₃As₃Cu₂O₈)
Molecular formula = C₄H₆As₆Cu₄O₁₆
Answer:
1.36 × 10³ mL of water.
Explanation:
We can utilize the dilution equation. Recall that:
Where <em>M</em> represents molarity and <em>V</em> represents volume.
Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:
Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
Convert this value to mL:
Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.
Answer: 1.875 moles
Explanation:
2 NaN3(s) → 2 Na(s) + 3 N2(g)
From the equation above, Sodium azide has a chemical formula of NaN3 while nitrogen gas has a chemical formula of N2.
Therefore, If on decomposition
2 moles of NaN3 produce 3 moles of N2
1.25 mol of NaN3 produce Z moles of N2
To get the value of Z, cross multiply
Z x 2 moles = 3 moles x 1.25 moles
2 moles•Z = 3.75 moles²
Divide both sides by 2 moles
2 moles•Z/2 moles = 3.75 moles²/2 moles
Z = 1.875 moles
Thus, 1.875 moles of N2 are produced by the decomposition of 1.25 mol of sodium azide
