Answer:
import java.util.*;
public class Country
{
public static void main(String args[])
{
char ch,temp;
int flag = 0;
String country;
ArrayList<String> countries = new ArrayList<String>();
Scanner sc = new Scanner(System.in);
do
{
System.out.println("enter the country you have visited:\t");
country = sc.next();
for(int i=0;i<countries.size();i++)
{
if(countries.get(i).equals(country))
{
System.out.println("you have already entered the country");
flag = 1;
break;
}
}
if(flag == 0)
{
countries.add(country);
flag = 0;
}
System.out.println("want to add another country(y/n):\t");
ch = sc.next().charAt(0);
}while(ch!='n');
Collections.sort(countries);
System.out.println("Countries you have visited:\t"+countries);
System.out.println("Total number of contries visited:"+countries.size());
}
}
Explanation:
Answer:
vulnerability, risk
Explanation:
A vulnerability would be a misconfiguration of a system that allows the hacker to gain unauthorized access, whereas a risk is a combination of the likelihood that such a misconfiguration could happen, a hacker’s exploitation of it, and the impact if the event occurred.
Answer:
import java.util.Scanner;
import java.util.Arrays;
import java.util.Random;
public class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter low: ");
int low = scan.nextInt();
System.out.print("Enter high: ");
int high = scan.nextInt();
scan.close();
int rndnumbers[] = new int[10];
Random r = new Random();
for(int i=0; i<rndnumbers.length; i++) {
rndnumbers[i] = r.nextInt(high-low+1) + low;
}
for(int i=0; i<rndnumbers.length; i++) {
System.out.printf("%d: %d\n", i, rndnumbers[i]);
}
}
}
