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WITCHER [35]
3 years ago
12

An automobile depreciates, or loses value, as it gets older. Suppose that a particular automobile

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0
First we need to find what is 20% off $23,999
1) = 20/100 x 23,999= $4,799
To find the decrease over 6 years :
2)= $4,799 x 6 = $28,798.8

Finally
= 28,798.8-23,999= $4,799.8

$4,799.8 is the final value.
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-38 due to the fact the lower the number, the colder it is.

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A city is designing a new trail system that will be
lyudmila [28]

Step-by-step explanation:

the answer is 6.125 and its will be divided by 125

3 0
3 years ago
A bank is offering you an introductory credit card promotion. Your interest for the first year is 8%. But, at the beginning
Art [367]

Answer:

  • c) $22.50

Explanation:

<u>1. Calculate the monthly interest owed during year 1</u>

<u />

  • <em>Interest for first year: 8%</em>

  • The monthly rate is the yearly rate divided by 12: 8% / 12 = 0.08/12

  • The monthly interest owed is the monthly rate times the balance: (0.08/12)×$1,800 = $12.00

<u>2. Calculate the monthly interest owed during year 2</u>

<u />

  • <em>Interest for second year: 23%</em>

  • The montly rate is the yearly rate divided by 12: 23% / 12 = 0.23/12

  • The monthly interest owed is the monthly rate times the balance: (0.23/12)×$1,800 = $34.50

<u>3. Calculate the difference</u>

  • Difference in the monthly interest owed during year 1 and year 2 = $34.50 - $12.00 = $22.50

Hence, the answer is the option c) $22.50

7 0
3 years ago
Can someone explain how to solve this?
Dmitrij [34]

9514 1404 393

Answer:

  (2/3)(e^t +1)^(3/2)

Step-by-step explanation:

Use the substitution ...

  u = e^t +1

Then du = e^t and you are finding the integral of ...

  ∫u^(1/2)·du

which you know by the power rule is ...

  (2/3)u^(3/2) = (2/3)(e^t +1)^(3/2)

4 0
3 years ago
A line passes through (2, –1) and (8, 4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in stan
pentagon [3]
The point-slope form of a line is:

y-y1=m(x-x1),  where m=slope and (x1,y1) is any point on the line

First we need to find the slope, which is (y2-y1)/(x2-x1)

m=(4--1)/(8-2)

m=5/6 and we can use either point, I'll use (8,4)

y-4=(5/6)(x-8)

That is your equation in point-slope form.

Now the standard equation of a line is ax+by=c

y-4=(5/6)(x-8)  we can perform the indicated multiplication on the right side

y-4=(5x-40)/6  multiply both sides by 6

6y-24=5x-40  add 24 to both sides

6y=5x-16  subtract 5x from both sides

-5x+6y=-16  and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1

5x-6y=16
8 0
3 years ago
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