9514 1404 393
Answer:
6.64
Step-by-step explanation:
Perhaps you have ...

_____
Here, it is convenient to factor out 10^-19. If you like, a calculator or spreadsheet can figure this for you.
Answer:
1/6
Step-by-step explanation:
Well perpendicular lines are reciprocals of each other,
meaning if like k has a slope of -6 then line n will have a slope of positive 1/6.
<em>Thus,</em>
<em>line n has a slope of 1/6.</em>
<em />
<em>Hope this helps:)</em>
Number 8? I don't know which one you are talking about.
Answer:
$203.02
Step-by-step explanation:
Since the bank in question compounds interest continuously, the following equation should be used to determine the final balance (B) in April's account:

Where "e" is a mathematical constant approximated as 2.7183, "i" is the interest rate (1.5%) and "t" is the investment time in years (1):


April's balance would be $203.02 after one year.