a sphere of radius 5 cm is melted down and made into a solid cube. Find the length of a side of the cube.

Mathematics

1 answer:

Amanda [17]3 years ago

5 0

Answer:

the volume of sphere will be equal to that of the volume of cube as change in shape doesn't effect the volume.

using,

Volume of sphere = volume of cube.

= a^3

Step-by-step explanation:

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Which value is equivalent to: 1 1/2 divided by 4 1/2 x 1 1/3

Nostrana [21]

Answer:

The answer is 4/9

Step-by-step explanation:

Hi. Here's the work.

First turn everything into an improper fraction.

$1 \frac{1}{2}$ ÷ $4 \frac{1}{2} * 1 \frac{1}{3}$ = $\frac{3}{2}$ ÷ $\frac{9}{2} * \frac{4}{3}$

To divide fractions we multiply by the flipped version of the fraction, or the reciprocal.

$\frac{3}{2}$ ÷ $\frac{9}{2} * \frac{4}{3}$ = $\frac{3}{2} *\frac{2}{9} *\frac{4}{3}$

Now we just multiply the fractions!

$\frac{3 * 2 * 4}{2 * 9 * 3}$ = $\frac{4}{9}$

The answer is therefore 4/9. Please mark brainliest if possible and i hope you get a good grade on your homework. ;)

6 0

3 years ago

What percentage of the semi circle is shaded?

mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

$r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%$

$r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%$ (1)

Where:

$A_{h}$ - Area of the half cross, in square centimeters.
$A_{s}$ - Area of the semicircle, in square centimeters.
$r$ - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

$r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100$