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3 years ago

a sphere of radius 5 cm is melted down and made into a solid cube. Find the length of a side of the cube.

Mathematics

1 answer:

Amanda [17]3 years ago

5 0

Answer:

the volume of sphere will be equal to that of the volume of cube as change in shape doesn't effect the volume.

using,

Volume of sphere = volume of cube.

= a^3

Step-by-step explanation:

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How do I solve w(x)=4x+5; find w(-8)?

madam [21]

W(x) = 4x + 5

w(-8) = 4(-8) + 5 = -32 + 5 = -27

6 0

4 years ago

Use vectors to find the interior angles of the triangle with the given vertices. (Enter your answers as a comma-separated list.

SOVA2 [1]

Answer:

23.92°, 78.503°, and 77.577°

Step-by-step explanation:

The coordinates of the vertices of the triangle are;

X(-3, -5), Y(2, 6), Z(6, 3)

The vectors are;

z = $\left \langle 2 - (-3), 6 - (-5) \right \rangle$ = $\left \langle 5, 11 \right \rangle$

y = $\left \langle 6 - (-3), 3 - (-5) \right \rangle$ = $\left \langle 9, 8 \right \rangle$

x = $\left \langle 2 - 6, 6 - 3 \right \rangle$ = $\left \langle -4, 3 \right \rangle$

$cos (\alpha ) = \dfrac{z \cdot y}{\left | z \right | \times \left | y \right |}$

Therefore, we get;

$cos (\alpha ) = \dfrac{5 \times 9 + 11 \times 8 }{\left | \sqrt{5^2 + 11^2} \right | \times \left | \sqrt{9^2 + 8^2} \right |} = \dfrac{133}{\sqrt{146} \times \sqrt{145} } \approx 0.91409$

α = arccos(0.91490) ≈ 23.92°

γ = The angle between -y and x

-y = $\left \langle -9, -8 \right \rangle$

We get;

$cos (\gamma) = \dfrac{-y \cdot x}{\left | -y \right | \times \left | x \right |}$

Therefore;

$cos (\gamma) = \dfrac{-9 \times -4 + -8 \times 3 }{\left | \sqrt{(-9)^2 + (-8)^2} \right | \times \left | \sqrt{(-4)^2 + 3^2} \right |} = \dfrac{12}{\sqrt{145} \times \sqrt{25} } \approx 0.199309$

γ = arccos(0.199309) ≈ 78.503°

γ ≈ 78.503°

By angle sum property, β = 180° - (α + β)

β ≈ 180° - (23.92° + 78.503°) = 77.577°

β ≈ 77.577°

The interior angles are;

23.92°, 78.503°, and 77.577°

4 0

3 years ago

An insured's roof cost $4,000 when installed 5 years ago. It has been damaged by hail and must be replaced. The new roof will co

hoa [83]

Answer:

ACV=$4,500

Step-by-step explanation:

We have that the actual cash value (ACV) is defined as:

$ACV=\dfrac{R\times(E-C)}{E}$

Where:

$ACV =$ actual cash value

$R =$ replacement cost or purchase price of the item

$E =$ expected life of the item

$C =$ current life of the item

Then we have R=$6,000, C=5years, and to find the expected life of the item we can use the depreciating of the roof, then if the roof is depreciating $200 each year we just need to divide $4,000 by $200 to find the expected life of the roof:

$\dfrac{4,000}{200}=20$

Then the espected life of the roof is 20 years, with this result we have all the data, then:

$ACV=\dfrac{\$6,000\times (20-5)}{20}=\dfrac{\$6,000\times (15)}{20}=\dfrac{\$90,000}{20}=\$4,500$

Then the ACV is $4,500

5 0

4 years ago

All the members of a construction crew work at the same pace. Six of them working together are able to pour foundation in 22 hou

beks73 [17]

Answer:

All the members of a construction crew work at the same pace. Four of them working together are able to pour concrete foundations in 32 hours.

Step-by-step explanation:

8 0

3 years ago

The area of a rectangle is 30+12x what are 3 possibilities for the length and width of the rectangle

Stolb23 [73]

In order to find the three possibilities, you must first think of common factors between 30 and 12:

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 12: 1, 2, 3, 4, 6, 12

We can find three common factors between the two numbers: 2, 3, and 6. So these are three widths that we can use. The length can be found by factoring out the numbers from 30+12x (we can't factor out x):

30+12x=2(15+6x) Width: 2 Length: 15+6x

20+12x=3(10+4x) Width: 3 Length: 10+4x

20+12x=6(5+2x) Width: 6 Length: 5+2x

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3 years ago

a sphere of radius 5 cm is melted down and made into a solid cube. Find the length of a side of the cube.​

a sphere of radius 5 cm is melted down and made into a solid cube. Find the length of a side of the cube.