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2 years ago

Second derivative test for: y= e^x (x^2 -7x +13)

1 answer:

4 0

First derivative is e^x(x^2-7x+13)+e^x(2x-7)
Which can be simplified to e^x(x^2-7x+13+2x-7)
Second derivative is e^x(x^2-5x+6)+e^x(2x-5)
Which then can be simplified to e^x(x^2-3x+1)

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Does anybody listen to girl in red?

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Me!! whats your favorite song?

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2 years ago

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Sam earned $154 washing 7 cars. He earned the same amount for washing each car. Select all the equations that show reasonable es

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3 years ago

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Cheese pizza cost 6$ each and four topping pizza that cost $10 each. If you order c cheese pizzas and f four toppings how much w

son4ous [18]

Answer:

$Total = \$6c + \$10f$

Step-by-step explanation:

Given

$Cheese\ Pizza = \$6$

$Topping\ Pizza = \$10$

Required

Cost of c cheese and f topping pizza

Solving for c cheese pizza

If 1 cheese pizza costs $6,

c cheese pizza would cost $6 * c

Solving for f topping pizza

If 1 topping pizza costs $10,

f topping pizza would cost $10 * f

Hence:

$Total = \$6 * c + \$10 * f$

$Total = \$6c + \$10f$

<em>Hence, the total amount paid is: </em> $\$6c + \$10f$ <em></em>

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2 years ago

What is the contra positive of the statement if 9x=27, then x=3

Karo-lina-s [1.5K]

Answer:

If 9x is not =27, then x is not =3

Step-by-step explanation:

Going out on a limb here, please ignore if I'm missing it:

If 9x is not =27, then x is not =3

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3 years ago

Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be ac

Likurg_2 [28]

For this problem, the most accurate is to use combinations

Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are $nC_r = \frac{ n! }{r! (n-r)!}$

n represents the amount of things you can choose and choose r from them

You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

$P = \frac{_{117}C_3}{_{120}C_3}$

Where $_{117}C_3$ is the number of ways to select 3 non-defective components from 117 non-defective components and $_{120}C_3$ is the number of ways to select 3 components from 120.