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Maurinko [17]
2 years ago
15

Jerry played with 3 friends today, all at different times. He played with Tommy for 1 7/8 hours, then Nathan for 1 3/4 hours, th

en Chris for 3/2 hours.
How many hours did Jerry play with his 3 friends today?
Mathematics
1 answer:
nlexa [21]2 years ago
8 0

Answer:

4hrs 7 minutes and 30 seconds

Step-by-step explanation:

1 7/8 = (1=60) + (7/8 * 60) = 1 : 52:50 time played with Tommy   1 3/4 = (1=60 ) ( (3/4 * 60) = 1:45:00 time played with Nathan   3/2 = (3/2 *60) = 90 = 1:30:00 time played with Chris    Total played with 3 friends = 1:52:50 + 1:45:00+1:30:00= 4:07:50 = 4hrs 7 minutes and 30 seconds

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rosijanka [135]
7000

1/8th in percentage form is 12.5%
12.5% of 56000 is 7000
8 0
2 years ago
Jamie wants to build a rectangular fence around a new garden. He can afford at most 70
KonstantinChe [14]

Option B is correct. <em>Yes,</em><em> (9, 22) is a solution to the </em><em>inequalities</em><em> and the</em><em> measurements</em><em> will fit in the space. </em>

The formula for calculating the perimeter of the rectangular fence is expressed as:

A = 2(L + W) where:

L is the length

W is the width

If Jamie can afford at most 70feet to build a rectangular fence is expressed as:

2L + 2W ≤ 70

<em>We are to check if the garden measure 9 feet by 22 feet. To do this we are to substitute L = 9 and W = 22 into the formula to check if the result will be less than 70</em>

On substituting:

= 2(9) + 2(22)

= 18 + 44

= 62 feet

Since 63 feet is less than 70 feet, hence we can conclude that <em>Yes,</em><em> (9, 22) is a solution to the </em><em>inequalities</em><em> and the</em><em> measurements</em><em> will fit in the space. </em>

<em />

<em>Learn more here: brainly.com/question/17229451</em>

8 0
2 years ago
HELP ASAP!!! PLEASE CHECK ALL OF THEM!
pochemuha

Answer:

2.

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

+

X^2+4/x^2-4

= 3x^2+3/x^2-4

B. (F-g)(x)

X^2-7x+6-x - 6

= x^2 -8x

C. (Fg)(x)

(X^2-7x+6)(x-6)

= x^3-13x^2+48x-36

D. (H/p)(x)

X/x-1 / 2x/x+4

X/x-1 / x+4/2x

= X^2+4x/2x^2-2x

3.

A. (F+g)(3)

X^2+1 + x-4

3^2+1 + 3-4

10 -1

= 9

B. (f-g)(0)

X^2+1 - x-4

0+1 -0-4

1-4

= -3

C. (Fg)(-k)

(X^2+1) (x-4)

(-k^2+1) (-k-4)

K^3+4k^2-k-4

D. (F/g)(k-2)

X^2+1 /x-4

K-2^2+1 / k-2 -2

= K^2-4k+5 / k-4

Step-by-step explanation:

8 0
3 years ago
Use the Distance Formula to find the distance to the nearest tenth between A(-7, -4) and B(-2, 0).
goldenfox [79]
A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
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<u>The surface area of the region he will paint is 900 sq.ft.</u>

<u>Step-by-step explanation:</u>

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5 0
2 years ago
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