Answer:
Suppose that logb b = x.
bx = b (Use the definition of a logarithm.)
bx = b1
x = 1 (Use the common base property.)
So, logb b = 1.
The area of a parallelogram is just:
A=bh, we are given b=3ft, so b=36in and A=324in^2 so
324=36h dividing both sides by 36
h=9
So the height is 9 inches.
Answer:
8.80 if it's the 40°/.
2.20 if it's the 10°/. processing fee
13.20 for how much he paid
The answer is A) because 98% of 300 is 294 and 1% of 300 is 3; first just divide 294 by 98% (.98) and u get 300 then multiply 300 by 1% (.01) and u get 3
Use the chain rule:
<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)
<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'
<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that
<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6) → <em>y(u(x))</em> = tan(<em>u(x)</em> )
By the chain rule,
<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>
and we have
<em>y(u)</em> = tan(<em>u</em>) → <em>y'(u)</em> = sec²(<em>u</em>)
<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6 → <em>u'(x)</em> = 2<em>x</em> - 5
Then
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)
or
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
as we found earlier.
