Find the 13th term of the sequence 8, -16, 32, -64, ...
2 answers:
This is a geometric sequence because dividing any term by the previous term results in a constant called the common ratio. Any geometric sequence can be expressed as: a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number. The common ratio,r, is -16/8=32/-16=-64/32=-2, and the first term, a, is 8 So the rule for this sequence is: a(n)=8(-2)^(n-1), so the 13th term is: a(13)=8(-2^12) a(13)=32768
The pattern is to multiply by -2 each time 8 -16 32 -64 128 -256 512 -1024 2048 -4096 8192 -16384 32768 Answer is A
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