You would use PEMDAS
But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57
Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57
Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57
Now you can add all of the numbers together
32➕504=536
536➕57=593
Your answer is 593
Hope this helps! :3
Answer:
289/290
Step-by-step explanation:
Given that the chance of Donnell being selected is 1/290
then P( Donnell being selected )= 1/290
Since Donnell and Maria are both member of a population.
from probability theorem which gives the likely hood of an event to happen which cannot be more than 1, then the probability of Donnell and Maria to be selected is 1
P(Donnell and Maria)= 1
But the chance of Donnell being selected is 1/290
Then,
1/290 + P(Maria)= 1
P(Maria)= 1-(1/290)
= 289/290
the chance of Maria being selected is 289/290
Answer: n = -6
Step-by-step explanation:
3n+14=-4
Subtract 14 from both sides.
3n+14-14=-4-14
Simplify
3n=-18
Divide both sides by 3
3n/3 = -18/3
n=-6
