S- and P-Block elements are known as Representative elements.
Groups 1-2 and Groups 13-18
Answer:
LR is Na₃PO₄
Explanation:
A quick way to determine the limiting reactant in a process is to convert reactant values to moles and then divide by the respective coefficient of the balanced equation. The smaller number of the division is the limiting reactant. For the given reaction, the rxn ratio of reactants is 1:1 so only the smaller mole value gives limiting reactant. However, if the reaction is NOT 1:1 the one must divide by respective coefficient to identify the smallest value and the limiting reactant.
This problem:
FeCl3(aq) + Na3PO4(aq) => FePO4(s) + 3 NaCl(aq)
Given: 27.8g 61.9g
moles: 27.8g/162.2g/mole 1.9g/163.94g/mole
= 0.1714 mole = 0.0116 mole
÷ coef. => 0.1714/1 = 0.1714 => 0.0116/1 = 0.0116
smaller value is LR => => => => => => LR is Na₃PO₄
Hope this helps. Doc :-)
Answer:
This tells us that for every 2 moles of potassium chlorate that are decomposed, then 3 moles of oxygen gas is produced.
The salt makes it rise and
Answer:
There will be produced 1.71 moles of B which contain 1.03×10²⁴ molecules
Explanation:
The example reaction is:
2A → 3B
2 moles of A produce 3 moles of B
If we have the mass of A, we convert it to moles and then, we make the rule of three: 29.2 g / 25.6g/mol = 1.14 moles
Therefore 2 moles of A produce 3 moles of B
1.14 moles of A will produce (1.14 . 3) / 2 = 1.71 moles of B are produced
Now we can determine, the number of molecules
1 mol has NA molecules (6.02×10²³)
1.71 moles have (1.71 . NA) = 1.03×10²⁴ molecules
