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3 years ago

Please help with 1 chemistry question thank you!

Chemistry

1 answer:

ale4655 [162]3 years ago

7 0

Here are the CORRECT names and molecular formulas

carbonate: $CO_3^{2-}$
bicarbonate: $HCO_3^{-}$

Choice 1 is incorrect

nitrite: $NO_2^{-}$
nitrate: $NO_3^{-}$

Choice 2 is incorrect

sulfite: $SO_3^{2-}$
sulfide: $S^{2-}$

Choice 3 is incorrect

By process of elimination, you can infer choice 4 is correct.

Actually, choice 4 is the only choice that displays the correct name and formula.

Have an awesome day! :)

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3.50 moles of Ca = ? grams Ca

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The mass of 3.5 moles of Ca is 140 g to two significant figures.

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3 years ago

calculate the molar mass of nickel (iii)oxide to the nearest tenth place. Give both the numerial value and the units

maksim [4K]

Nickel (Ni) has the charge as +3 while oxygen (O) has -2. Hence, the chemical formula for the nickel (iii) oxide is Ni₂O₃.

molar mass of Ni = 58.69 g/mol
molar mass of O = <span>15.99 g/mol

number of Ni atoms in </span>Ni₂O₃ = 2
Molar mass of Ni in Ni₂O₃ = 2 x 58.69 g/mol = 117.38 g/mol

number of O atoms in Ni₂O₃ = 3
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4 years ago

7.0 mol Mn reacts with 5.0 mol

Elenna [48]

The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.

<h3>What is a limiting reagent?</h3><h3 />

In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.

In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.

Thus, the moles of oxygen consumed by 7 moles of Mn is:

2 moles Mn = 1 mole O₂

7 moles Mn = 3.5 moles O₂

The available moles of O₂ = 5 mol.

The remaining moles of O₂ = 5-3.5 moles

The remaining moles of O₂ = 1.5 moles

The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.

The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂

1 mole O₂ = 2 moles MnO

1.5 moles O₂ = 2 * 1.5 moles MnO

1.5 moles O₂ = 3 moles MnO

Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.

Learn more about stoichiometric law, here:

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2 years ago

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