According to Avogadro's law 1 mole contains 6.022 ×10^23 particles
1 mole of carbon = 44.01 g/ mol
Therefore;
44.01 g = 6.022 ×10^23 molecules
Hence, 1.68×10^26 molecules will have a mass of ;
(44.01 × 1.68×0^26) / 6.022×10^23
= 1.228 × 10^4 molecules
Answer:
94448421.2201
Explanation:
multiply the value in kilometers by the conversion factor '0.62137119223684'.
So, 152000 kilometers = 152000 × 0.62137119223684 = 94448.42122 miles.
Valance electron are called
Given that CaCl2 = 2.46 m
Therefore 2.46 mole of CaCl2 present in 1.00 g of solution
Mass of 2.46 mole CaCl2= number of mole * molar mass
= 2.46 mole * 110.98 g/mol
= 273.01 g
Mass of water or solvent = mass of solution – mass of solute
= 1000 g -273.01 g
= 726.99 g
Mole of water = amount in g / molar mass
= 726.99 g/18.02 g/ mole
= 40.34 moles
Mole fraction of CaCl2 = number of mole of CaCl2 / total moles
= 2.46 /2.46+40.34
= 2.46/42.8
= 0.057